Answer:
ΔSTR is similar to ΔRTQ
Step-by-step explanation:
Given QRS is a right angled triangle. we have to find the similarity statement ΔSTR ~ Δ__
Let ∠S=x
In ΔSTR, by angle sum property
∠S+∠STR+∠SRT=180°
⇒ ∠SRT=90°-x
In ΔSRQ, by angle sum property
∠S+∠R+∠Q=180°
⇒ ∠Q=90°-x
In ΔSTR and ΔRTQ
∠SRT=∠Q=90°-x (proved above)
∠STR=∠RTQ (each 90°)
RT=RT (common)
Hence, by AAS rule ΔSTR≅ΔRTQ
∴ ΔSTR is similar to ΔRTQ
Option 4 is correct.
Answer:
475 ft
Step-by-step explanation:
= 
cross multiply
2x = 950
x = 475
You need to define is the values given stand for the meaure of the angles in degrees or for the lengths of the sides.
It it is fhe former, then you can write:
5s + 20s + s + 24° = 180°
=> 26s + 24° = 180°
=> 26s = 180° - 24°
=> 26s = 156°
=> s = 156° / 26 = 6°
If it is the latter, then you have to use the law of cosines and or the law of sines.
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Answer:
22.1
Step-by-step explanation:
divide 16.9 by 13= 1.3
17x1.3=22.1