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frosja888 [35]
3 years ago
5

What equation in slope intercept form represents the line that passes through the points (3, -2) and (1, -3)

Mathematics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

What equation in slope intercept form represents the line that passes through the points (3, -2) and (1, -3)

A. y = - 1/2x - 7/2

B. - 1/2x + 7/2

C. 1/2x - 7/2                                                  this its the correct answer c

D. 1/2x + 7/2

Step-by-step explanation:

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on field day, 1/10 of the students in Mrs. Brown's class competes in jumping events, 3/5 of the student competes in running even
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1/10 + 1/10 = 2/10
10 / 5 = 2
3/5 = 6/10
2/10 + 6/10 = 8/10
10/10 - 8/10= 2/10
6 0
3 years ago
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Convert 5820 grams to kilograms.
mr_godi [17]

5.82 Kg

because 1Kg= 1000g

5 0
3 years ago
15. Which of the following equations was
arlik [135]

Answer:

B

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c (m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 6) and (x₂, y₂ ) = (6, 0)

m = \frac{0-6}{6-0} = \frac{-6}{6} = - 1

Note the line crosses the y- axis at (0, 6 ) ⇒ c = 6

y = - x + 6 or y = 6 - x ⇒ B

3 0
3 years ago
Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3
solmaris [256]

Given:

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

Now,

\cos (u)=-\sqrt{1-\sin^2 (u)}

\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}

\cos (u)=-\sqrt{1-\dfrac{49}{625}}

\cos (u)=-\sqrt{\dfrac{625-49}{625}}

On further simplification, we get

\cos (u)=-\sqrt{\dfrac{576}{625}}

\cos (u)=-\dfrac{24}{25}

Similarly,

\sin (v)=-\sqrt{1-\cos^2 (v)}

\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}

\sin (v)=-\sqrt{1-\dfrac{16}{25}}

\sin (v)=-\sqrt{\dfrac{25-16}{25}}

\sin (v)=-\sqrt{\dfrac{9}{25}}

\sin (v)=-\dfrac{3}{5}

Now,

\cos (u-v)=\cos u\cos v+\sin u\sin v

\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)

\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}

\cos (u-v)=\dfrac{1 17}{625}

Therefore, the value of cos (u-v) is 0.1872.

6 0
3 years ago
What is 9-3y=x I don't know this one
torisob [31]
The answer is 
y= - x-9/3 I believe.
1- Subtract 9 from both sides.
-3y = x - 9
2- Divide both sides by -3
y = - x-9/3
4 0
4 years ago
Read 2 more answers
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