Let u = x², then we would have u² + 5u - 6 = 0
From here, we can factor it and get us (u-1)(u+6) = 0
So our solution for u is u = -6 or 1.
Now substitute u back to x².
x² = -6 or 1
x = ±√(-6) or ±√1
Since ±√(-6) is not real number, we ignore it.
Which leave us x = ±√1 = <span>±1
So our real solution is x = -1 or 1.</span>
Answer:
![\sqrt{125}](https://tex.z-dn.net/?f=%5Csqrt%7B125%7D)
Step-by-step explanation:
Use Pythagorean theorem since you have a right triangle
= ![10^{2} + x^{2}](https://tex.z-dn.net/?f=10%5E%7B2%7D%20%2B%20x%5E%7B2%7D)
225 = 100 +
so x = ![\sqrt{125}](https://tex.z-dn.net/?f=%5Csqrt%7B125%7D)
Disagree.
b/8 = 56; multiply both sides by 8 to solve for b, and you get b = 448
Answer:
y=1.5x=4
Step-by-step explanation:
Answer:
answer is c
Step-by-step explanation: