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3 years ago

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During what stage of succession would you expect to find only moss, lichen, and other small plants? early/pioneer stage , middle

/intermediate stage late/climax stage , you will never see these types of trees again,

1 answer:

kirill115 [55]3 years ago

4 0

Primarily succession or <span>early/pioneer stage</span>

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The S-P interval of seismic waves recorded at a seismometer is 8 minutes. Approximately how far away is the earthquake’s epicent

Alex787 [66]

According to the equation the correct answer with the interval registered in minutes is: C
8=0.00146 (distance to epicentre) <=> distance to epicentre=8÷0.00146 <=>5479,45 km

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Which structure helps to prevent food from entering the trachea during swallowing?

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Autopsy conducted on an individual who had died of pneumonia revealed bluish-green pus filling the lung. The causative agent of

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Answer:

The agent causing the pneumonia, where bluish-green pus was found, is most likely Pseudomonas aeruginosa.

Explanation:

Pseudomona aeuriginosa is a gram-negative bacteria that is one of the main causes of hospital-acquired infections, including pneumonias in mechanically ventilated patients.

One of the characteristics of P. aeuriginosa is the formation of a bluish-green pus, since it has the capacity to form cyanide-based blue pigment upon contact with the organic tissues it infects. This is the reason why previously P. aeruginosa was called a pyocyanic bacillus.

<em> The other options are not correct because the only bacterium that produces blue-green pus is P. aeruginosa.</em>

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Which piece of equipment would be best used to seperate the mixture of salt water?

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In a hardy-weinberg population with two alleles, a and a, that are in equilibrium, the frequency of the allele a is 0. 3. What i

zavuch27 [327]

Here, given-

homozygous alleles 'a' have a frequency of 0.3.

Also the alleles are in equilibrium in a Hardy-Weinberg population. The frequency of individuals that are homozygous for this allele are= 0.49.

The Hardy-Weinberg equilibrium can be defined as the principle which states that the variation in the genetic makeup of a population remains constant and unchanged till there are no external interferences, influencing the population.

Calculation-

$p + q = 1\\0.3 + q= 1\\q= 1- 0.3\\\\q= 0.7$

Then to find the frequency of the individuals homozygous for this allele the following formula needs to be used-

$p^{2} + 2pq + q^{2} =1$

$p^{2} = dominant homozygous frequency\\2pq= heterozygous frequency\\q^{2} = recessive homozygous frequency\\$

Thus, the individuals homozygous for the allele can be calculated by $q^{2} = (0.7)^{2} \\= 0.49$

Learn more about the Hardy-Weinberg equilibrium here-

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