What is an advantage of using a checking account

Andrej [43]

<span>0.00041649312 on a calc unless u wanna simplify :)

hope i helped best of luck :)

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4 0

2 years ago

A triangular sail has two sides the same length. The third side is 9ft shorter than either of the equal sides. The perimeter of

jeka94

$a-length\ one\ of\ the\ same\ sides\\\\a-9-length\ of\ third\ side\\\\a+a+a-9=63\ \ \ \ \ \ |add\ 9\\a+a+a=63+9\\3a=72\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |divide\ by\ 3\\a=24\\\\a-9=24-9=15\\\\The\ shortest\ side\ is\ 15.$

4 0

2 years ago

The shape of the distribution of the time required to get an oil change at a 20 minute oil change facility. However, records ind

Katyanochek1 [597]

Answer:

For a mean oil change time of 20.51 minutes there would be a 10% chance of being at or below

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .