Answer:
Option 3 (7,2) is right answer.
Step-by-step explanation:
Given two equations
3x-2y=17 ... i
x-3y=1 ... ii
We can solve this by elimination.
coefficients of x are 3 and 1 with LCD = 3
Hence multiply ii equation by 3
3x-9y = 3 ... iv
3x-2y = 17 ... i
Subtract i from iv
-7y = -14
Divide by -7
y =2
Substitute in ii
x-3(2) = 1
x=7
Hence solution is (7,2)
Verify:
We can verify our solution by substituting in i and ii.
3(7)-2(2) = 17 and 7-6 =1
Verified
Apply the radical rule to separate terms:
Cubicroot(-27) and cubic root(n^27)
Cubicroot(-27) = -3
Now you have -3 cubicroot(n^27)
Using the exponent rule
N^27 can be rewritten as (n^9)^3
Now you have -3 cubicroot((n^9)^3)
The cubic root and the 3rd power cancel out to get the final answer of
-3n^9
This equation simplified would be
-y(-5y+6)
Answer:
the answer is 3/2........
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