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Andreyy89
3 years ago
6

How do you determine the common difference for an arithmetic sequence?

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0

Answer:

Common difference(d) is:

a2-a1=a3-a2=a4-a3= d

d is constant till  

a_n-a_n_-_1 =d

Step-by-step explanation:

An arithmetic sequence or arithmetic progression is the sequence, whose difference of consecutive terms called common difference is constant throughout the sequence.

Considering, the sequence    a_1,a_2,a_3,a_4,.......a_n

a2-a1=a3-a2=a4-a3= d

     d= common difference.

we can find any  n^t^h term in the sequence by using the formula

a_n=a_1+(n-1)d

where  a_n= any n^t^h term

             n\\=Number of terms

            d=common difference

           a_1= first term

Also sum of n terms of A.P can be find by the formula:

              S_n=\frac{n}{2} [2a+(n-1)d]

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Will make brainliest if answer correctly
Sergeeva-Olga [200]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
Use the substitution method to solve the system of equations. Choose the correct ordered pair.
motikmotik
Ur gonna have to pick an equation and solve for a variable.

2x - 2y = 6
2x = 2y + 6 ...divide everything by 2 because u want x by itself
x = y + 3

now we sub y + 3 in for x in the other equation
14x - 2y = 78
14(y + 3) - 2y = 78...distribute thru the parenthesis
14y + 42 - 2y = 78...subtract 42 from both sides, cancelling the 42 on the left
        -42          -42
-----------------------
14y - 2y = 36 ...simplify
12y = 36...divide by 12 on both sides, cancelling out the 12 on the left
y = 36/12
y = 3

now , we already know that x = y + 3...and we know y = 3...so sub in 3 for y and solve for x
x = y + 3
x = 3 + 3
x = 6

solution is (6,3)

it is always a good idea to check ur answer by subbing it into one or both of the equations to see if it is correct
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4 0
3 years ago
Read 2 more answers
Simplify sin(3pi minus x)
Slav-nsk [51]

Answer:

sinx

Step-by-step explanation:

hello :

note :

for all x in ℝ :   1) sin(x+2π) = sinx        2)  sin(π-x) = sinx

in this exercice :

3π - x = 2π+(π - x)

sin(3π - x) = sin(2π +(π - x)) =sin(π-x) = sinx

8 0
3 years ago
Find the equation of the line
kirill115 [55]

Answer:

Step-by-step explanation:

The line is passing through 2 points: (0,9 and (3,3)

slope=(9-3)/(0-3)=-2

equation is : y-9=-2(x-0) or y=-2x+9

8 0
2 years ago
a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

4 0
2 years ago
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