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motikmotik
4 years ago
9

There are 6 times as many dogs as cats. If the total number of dogs and cats is 21. How many dogs are there

Mathematics
2 answers:
zmey [24]4 years ago
6 0

Answer: There are 18 dogs.

Step-by-step explanation:

Let x be the number of cats.

Given : There are 6 times as many dogs as cats.

Number of dogs = 6x

If the total number of dogs and cats is 21, then we have

x+6x=21\\\\\Rightarrow\ 7x=21

We divide both sides by 7 , we get

x=3

Now, number of cats = 3

Number of dogs = 6(3)=18

Hence, there are 18 dogs.

Lostsunrise [7]4 years ago
4 0

18, because cats would be 3, and then the dogs would be 6 times that, which would be 18.  18 + 3 = 21.

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tatiyna
Subtract 6 n both sides and 6- 252 is your answer....
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4 years ago
Read 2 more answers
The diagram below shows a wall with a
yulyashka [42]

Answer:  H (131.125 ft^2)

Step-by-step explanation:

first, you need to find the area of the wall

wall:

A=Lw  (length times width)

A= 9.75 x 15.5  (I changed them into decimals)

A = 151.125

now you need to find the area of the window

window:

A = Lw

A = 4 x 5

A = 20

now you need to subtract the area of the window from the area of the wall to find the amount of space you need to cover with wallpaper

151.125 - 20 = 131.125

6 0
4 years ago
HELP PLS!! <br> Adding and subtracting vectors in component form
tino4ka555 [31]
<h3>Answers:</h3>
  1. u+v = <3,12>
  2. w+g = <7,0>
  3. g-z = <2,4>
  4. v-u = <9,4>
  5. y+v = <7,9>
  6. u+v+y = <4,13>

===================================================

Explanation:

Problem 1

If we had the two vectors u = <a,b> and v = <c,d>, then adding them gives us

u+v = <a+c,b+d>

The corresponding coordinates pair up and add together.

In this case we have

u = <-3,4>

v = <6,8>

So,

u+v = <-3+6,4+8>

u+v = <3,12>

---------------------

Problem 2

We follow the same idea as the previous problem.

w = <8,-1>

g = <-1,1>

w+g = <8+(-1),-1+1>

w+g = <7,0>

---------------------

Problem 3

Similar to addition, subtracting vectors has us subtract the corresponding coordinates.

The general template is:

u = <a,b>

v = <c,d>

u-v = <a-c,b-d>

With this in mind, we can say the following:

g = <-1,1>

z = <-3,-3>

g-z = <-1-(-3),1-(-3)>

g-z = <-1+3,1+3>

g-z = <2,4>

---------------------

Problem 4

Follow the same idea as problem 3 above.

v = <6,8>

u = <-3,4>

v-u = <6-(-3),8-4>

v-u = <6+3,8-4>

v-u = <9,4>

---------------------

Problem 5

Refer to problem 1.

y = <1,1>

v = <6,8>

y+v = <1+6,1+8>

y+v = <7,9>

---------------------

Problem 6

u = <-3,4>

h = v+y = y+v = <7,9>

u+v+y = u + h

u+v+y = <-3,4> + <7,9>

u+v+y = <-3+7,4+9>

u+v+y = <4,13>

Notice how I built off the result of problem 5 when I used h = v+y. The vector v+y is the same as y+v because the order of addition doesn't matter. Also, the idea mentioned in problem 1 can be extended for more than two vectors.

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3 years ago
If T is the midpoint of CE then CT=TE
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Answer: true statement
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Helen [10]
5.5/12 = x/60

One hour/ 12 minutes = 5

5.5•5=27.5

Caribe reads 27.5 pages per hour.
8 0
3 years ago
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