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3 years ago

What is the midpoint of the points given in the image if A is (8,7) and B is (9,3)?

Mathematics

1 answer:

laila [671]3 years ago

7 0

Answer:

(-1,4)

Step-by-step explanation:

basically take x and subtract it from the other x and in the same order subtract the y's

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VW = z and UX= z - 10

Brilliant_brown [7]

What are you trying to say?

3 0

4 years ago

Express 17.16 as a mixed number in lowest terms

pentagon [3]

Answer:

$17\frac{4}{25}$

Step-by-step explanation:

First write 0.16 is a fraction. Start by dividing 16 by 100.

$0.16\\=\frac{16}{100}\\=\frac{16}{100}*\frac{\frac{1}{4}}{\frac{1}{4}}\\=\frac{4}{25}$

Now adding the 17 to that fraction that is equivalent to 0.16:

$17+\frac{4}{25}\\=17\frac{4}{25}$

8 0

3 years ago

Read 2 more answers

Round 18.159 to the nearest tenth

Mandarinka [93]

Answer:

18.2

Step-by-step explanation:

A tenth is the first decimal, on the right of your unit. 5 to the sky (round up) 4 to the floor (round down)

5 0

2 years ago

What is the y-intercept of f(x)=5 x (1/6x)

Colt1911 [192]

Answer:

(5, 0)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

7 0

3 years ago