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Basile [38]
4 years ago
5

The distance between the orgin (0,0) and the pt (c,d) is

Mathematics
1 answer:
Aleks [24]4 years ago
6 0
Do you have a picture of the graph?
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What is the factor of 12
balu736 [363]

The factor of 12 is 1, 2 , 3 , 4 , 6 , 12

Hope it helps.

7 0
3 years ago
Hi. Could you please help me with this question??
Liula [17]
B) 23
Add what you know together, 6 + 2 + 2 + 2 + 3.5. Fill in what you don’t by looking at other sides. 3.5 + 2 + 2.
5 0
3 years ago
Simplify the expression.. help me pleaseee 3
oksian1 [2.3K]

Answer:

C. 2.245 * 10^6

Step-by-step explanation:

(2.2)(10^6) + (4.5)(10^4) = 2245000

Simplify to match answer choices.

8 0
4 years ago
One year there was a total of 59 commercial and noncommercial orbital launches worldwide. In addition, the number of noncommerci
Lina20 [59]

Answer:

The number of commercial orbital launches is equal to 19 and the number of noncommercial orbital launches is equal to 40.

Step-by-step explanation:

IMPORTANT INFORMATION: The number of noncommercial orbital launches was two more than twice the number of commercial orbital launches.

Let's say that the number of commercial orbital launches is equal to x. Now, the number of noncommercial orbital launches is equal to 2x+2.

We are told that if we add the number of commercial and noncommercial orbital launches together we will get 59.

Therefore, if we add 2x+2 with x we should get 59:

2x+2+x=59

3x+2=59

3x=57

x=19

This is how we can come to the answer that the number of commercial orbital launches is equal to 19 and the number of noncommercial orbital launches is equal to 40 (2x+2=2*19+2=38+2=40).

Hope this helps!

4 0
3 years ago
Monthly budget- Total income 2910. 52 Mortgage 1100, childcare 682, Electric 200, phone 188, cable/tv 190. 76, food and grocerie
diamong [38]
Take 2910 and subtract 52-1100-682-200-188-190-76-450-121-90-65... you should get -304, i’m not sure what your question is asking, but if you take your income minus cost per month you should get your answer
8 0
3 years ago
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