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Natalka [10]
4 years ago
10

Which expression shows a way to find 2813×7

Mathematics
2 answers:
Mandarinka [93]4 years ago
5 0

Answer:

19,691

Step-by-step explanation:

omeli [17]4 years ago
4 0

Answer:

2813 x 7 = 19691

Hope this helps!

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Read the proof<br><br> Given: AE EC; BD DC<br> Prove: triangle AEC ~ triangle BDC
Sidana [21]

Answer:

EAC LINE TO~triangle BDC

Step-by-step explanation:

B AND D IS NOT UQAUL

AEC IS THE FIRST GIVEN

SO YOU FINE THE ALL RIGHT ANGLES RIGHT

7 0
3 years ago
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Solve the proportion. 2/3=3/q
Montano1993 [528]

Answer:

below

Step-by-step explanation:

q=9/2

6 0
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Help me pls I need to get my grade up before July 11th so help ASAP​
devlian [24]
Second option:
-7x^2+4x+2
8 0
2 years ago
Use technology to approximate the solution(s) to the system of equations to the nearest tenth of a unit
PSYCHO15rus [73]

Question:

Use technology to approximate the solution(s) to the system of equations to the nearest tenth of a unit.

Select all that apply.

f(x)=log x

g(x)=|x-3|

(3.6,0.6)

(-2.6,0.4)

(-3.6,0.6)

(2.6,0.4)

(4.5,-1.5)

Answer:

Option A : (3.6,0.6) is the solution to the system of equations.

Option D: (2.6,0.4) is the solution to the system of equations.

Explanation:

The two equations are f(x)=log x and g(x)=|x-3|

To determine the solution of the system of equations using technology, let us plot the equations in the graphing calculator.

The solution of the system of equations is the intersection of the two lines.

Thus, from the graph, we can see that the two lines f(x) and g(x) intersect at the points (2.587,0.413) and (3.55,0.55)

Rounding off the solution to the nearest tenth, we get,

(2.6,0.4) and (3.6,0.6)

Thus, the solution to the system of equations is (2.6,0.4) and (3.6,0.6)

Hence, Option A and Option D are the correct answers.

3 0
4 years ago
Verify the trigonometric identity. convert the left side of the relationship to look like the right side.
Tomtit [17]

Answer:

Verified

Step-by-step explanation:

Use \tan{x}=\frac{\sin{x}}{\cos{x}}  , \sin^2{x}+\cos^2{x}=1 and \sec{x}=\frac{1}{\cos{x}}

LHS=\tan^2{x}+1=\frac{\sin^2{x}}{\cos^2{x}} + 1=\frac{\sin^2{x}+\cos^2{x}}{\cos^2{x}}=\frac{1}{\cos^2{x}}=\sec^2{x}=RHS

5 0
3 years ago
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