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3 years ago

State the domain of the relation (-4,3) (-1,0) (0,-2) (2,1) (4,3)

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

7 0

The domain: {-4; -1; 0; 2; 4}
The range: {-2; 0; 1; 3}
Yes. The relation is a function.

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The perimeter of this hexagon is 52in. Each longer side measure 1 in. less than 4 times the length of a shorter side. Find the l

amm1812

Answer:

x=4.5 inches

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The perimeter of a hexagon is the sum of its six length sides

Let

x ----> the length of a shorter side

y ---> the length of a longer side

The perimeter of the hexagon is equal to

$P=4x+2y$

$P=52\ in$

$52=4x+2y$ ---->equation A

Each longer side measure 1 in. less than 4 times the length of a shorter side

$y=4x-1$ ----> equation B

substitute equation B in equation A

$52=4x+2(4x-1)$

Solve for x

$4x+8x=52+2\\12x=54\\x=4.5\ in$

7 0

3 years ago

Consider a triangle ABC with AB = 2, BC = 5, and AC = 6. If the triangle is rotated around AB, what is the volume of the solid t

geniusboy [140]

Answer:

The volume of the solid generated is 52.33 cubic units.

Step-by-step explanation:

Given the triangle ABC

AB = 2

BC = 5

AC = 6

If the ABC triangle is rotated around AB, it would generate a circular cone. The volume of the generated cone can be computed using the following formula.

$V=\frac{1}{3}\pi r^{2} h$

From the given triangle,

AB = height = 2

BC = radius = 5

So,

Putting these values in $V=\frac{1}{3}\pi r^{2} h$ would yield the volume of a circular cone.

$V=\frac{1}{3}\pi r^{2} h$

$V=\frac{1}{3}(3.14) (5)^{2} (2)$

$V=52.33$

Therefore, the volume of the solid generated is 52.33 cubic units.

Keywords: triangle, volume, solid, right circular cone

Learn more about volume of solids from brainly.com/question/14311251

#learnwithBrainly

7 0

3 years ago

Determine the formula, in terms of x, that best describes the area of the plot.

liq [111]

The area of a plot is the amount of space on the plot

The area of the plot is 2x^2 -x - 1

<h3>How to determine the area</h3>

The dimensions of the plot are given as:

Length=2x+1

Width=x-1.

The area of the plot is the product of its dimension.

So, we have:

$Area = (2x + 1)(x - 1)$

Expand

$Area = 2x^2 - 2x + x - 1$

Evaluate the like terms

$Area = 2x^2 -x - 1$

Hence, the area of the plot is 2x^2 -x - 1