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Sonja [21]
3 years ago
8

You have $10,000 to deposit in a savings account that earns simple interest at a rate of 4.5% per year. how much interest will b

e in the account after 2 years?
Mathematics
1 answer:
postnew [5]3 years ago
7 0
0.045×10,000×2 =900..............
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3 years ago
Divide 36087 by 56 and verify the result by division algorithm.​
patriot [66]

Answer:

Do like this

Step-by-step explanation:

Hope it helps you

5 0
2 years ago
A​ town’s January high temperatures average 36 degrees​ (F) with a standard deviation of 10 degrees while in July the mean high
n200080 [17]

Answer:

55 degrees is more unusual in July as it is away from mean temperature as compared to January.

Step-by-step explanation:

We are given the following information in the question:

January:

Mean, μ = 36 degrees

Standard Deviation, σ = 10 degrees

July:

Mean, μ = 74 degrees

Standard Deviation, σ = 8 degrees

We calculate z scores corresponding to x = 55.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

January:

z_{score} = \displaystyle\frac{55-36}{10} = 1.9

July:

z_{score} = \displaystyle\frac{55-74}{8} = -2.375

Thus, 55 degrees is more unusual in July as it is away from mean temperature as compared to January.

3 0
3 years ago
A right triangle has one vertex on the graph of y = 9 - x^2 , x &gt; 0, at ( x , y ), another at the origin, and the third on th
jenyasd209 [6]

Answer:

  a.  A(x) = (1/2)x(9 -x^2)

  b.  x > 0 . . . or . . . 0 < x < 3 (see below)

  c.  A(2) = 5

  d.  x = √3; A(√3) = 3√3

Step-by-step explanation:

a. The area is computed in the usual way, as half the product of the base and height of the triangle. Here, the base is x, and the height is y, so the area is ...

  A(x) = (1/2)(x)(y)

  A(x) = (1/2)(x)(9-x^2)

__

b. The problem statement defines two of the triangle vertices only for x > 0. However, we note that for x > 3, the y-coordinate of one of the vertices is negative. Straightforward application of the area formula in Part A will result in negative areas for x > 3, so a reasonable domain might be (0, 3).

On the other hand, the geometrical concept of a line segment and of a triangle does not admit negative line lengths. Hence the area for a triangle with its vertex below the x-axis (green in the figure) will also be considered to be positive. In that event, the domain of A(x) = (1/2)(x)|9 -x^2| will be (0, ∞).

__

c. A(2) = (1/2)(2)(9 -2^2) = 5

The area is 5 when x=2.

__

d. On the interval (0, 3), the value of x that maximizes area is x=√3. If we consider the domain to be all positive real numbers, then there is no maximum area (blue dashed curve on the graph).

5 0
3 years ago
According to the U.S. Department of Agriculture in 2011, the cost of raising a child from birth to eighteen years of age is appr
My name is Ann [436]

Answer:

$234,900

Step-by-step explanation:

Quick Search on the internet

3 0
1 year ago
Read 2 more answers
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