There are 3 bracelets.
The first bracelet can occupy a position in 3 ways.
The second bracelet can occupy the remaining 2 positions in 2 ways.
The third bracelet can occupy the remaining position in 1 way.
The total number combinations is
3*2*1 = 6
Answer: 6
Answer:
This quadratic equation has 2 solutions.
Step-by-step explanation:
I assume the '?' in your question is meant to be power 2 (²), or else it would not be a quadratic equation. You could write it using the superscript version of 2.
We can solve this equation by expressing it in the form: ax² + bx + c
x² + 9x= -8
x² + 9x + 8 = 0
Now if you know the discriminant, you can simply plug in your values of a, b, and c to see how many solutions there are.
In this case, you would not need the discriminant as there are whole-number factors and hence this can simply be factorised.
x² + 9x + 8 = 0
(x + 8)(x + 1) = 0
For this equation to be true (= 0), x can equal -8 OR -1.
Hence, this quadratic equation has 2 solutions.
The answer is 16 can u give me brainliest hehehe
- 8(7k-5) + 7(7k-7) = 1 - 5k - k - 7
- 56k + 40 + 49k - 49 = 1 - 6k - 7
13k = 3
k = 3/13
i am a mathematics teacher. if anything to ask please pm me
Ok. Something times 90 = 7200.
Let something = x
90x = 7200
Divide both sides by 90.
90x/90 = 7200/90
x = 80
The other factor is 80.