Answer:
2x
Step-by-step explanation:
aka 2
You can take the log of the left and right hand side, and then apply the <span>logarithm rules:
log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)
log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
(x-1) log(9) + (2x+2) log(2) - 3x log(6) = 0
x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)
simplifying by writing log9 = 2log3 and log6 = log2+log3
x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) =
x= -2(log3 - log2) / (log3 + log2) = -2 log(3/2) / log(6)
So 6^x = 4/9
Answer:
I believe it's 4,080
Step-by-step explanation:
you just add the two numbers
In this problem, we let x be the number of half gallons of milk the store bought, and x-12 be the remaining half gallonsWe use the equation profit = revenue-cost
88.08=4.02(x-12)-2.60x88.08=4.02x-48.24-2.6x1.42x=88.08+48.24=136.32x=136.32/1.42=96Hence, the number of half gallons of milk the store bought is 96
