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What will be the value of x after the following code is executed? int x = 10; do { x *= 20; } while (x < 5); A. 10 B. 200 C.

dezoksy [38]

Answer:

Option B is the correct answer.

Explanation:

In the above code, the loop will execute only one time because the loop condition is false and it is the Do-While loop and the property of the Do-while loop is to execute on a single time if the loop condition is false.
Then the statement "x*=20;" will execute one and gives the result 200 for x variable because this statement means "x=x*20".
SO the 200 is the answer for the X variable which is described above and it is stated from option B. Hence it is the correct option while the other is not because--

Option A states that the value is 10 but the value is 200.
Option C states that this is an infinite loop but the loop is executed one time.
Option D states that the loop will not be executed but the loop is executed one time

6 0

3 years ago

Read 2 more answers

A line of code that begins with the while needs to end which symbol? # " : .

olga_2 [115]

<h2>A line of code that begins with the "while" needs to end with ":" symbol</h2>

Explanation:

In python, the while loop statement has ":" at the end of the line.

Syntax:

while expression:

code(s) or statement(s)

Example:

cnt = 0

while (cnt < 5):

print 'cnt:', cnt

cnt = cnt + 1

Like other programming languages, while loop works in the same way except that in python it comes alone with "else" statement. When the condition is false, "else" statement gets executed.

Example:

#!/usr/bin/python

cnt = 0

while cnt < 5:

print cnt, " is less than 5"

cnt = cnt + 1

else:

print cnt, " is not less than 5"

3 0

3 years ago

If I add a # symbol in front of the cells row/column, it will keep the value true.

jonny [76]

I think trueeeeeeeeeeeeeeeeee

3 0

3 years ago

Read 2 more answers

The instruction format of a computer is given by one indirect bit, opcode bits, register address bits, immediate operand bits an

oksian1 [2.3K]

Answer:

Following are the answer to this question:

Explanation:

A)

The memory size is 1 Giga Bytes which is equal to $2^{30}$

$\texttt{Number of address bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ Number of addresses}\\\\ \ \ \ \ 30 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2^{30}= 1073741824$

B) $\texttt{I \ \ \ Opcode \ \ \ Register address \ \ \ Immediate operand \ \ \ Memory address}\\\\\\\textt{1 \ bit \ \ \ \ \ \ 128 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2 \ bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 24 \ bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 30 \ bits}\\\\\\$ $= 2^7 \\\\ = 7 \ bits$

calculating the register Bits:

$= 64-(1+7+24+30)\\\\=64 -62\ \ bits\\\\= 2\ \ bits\\$

C)

Immediate value size while merging the additional benefit with the address field:

$= 2^{24} + 2^{30}\\\\= 2^{54}\\\\$ $\texttt{Range before combining(-,+) 24 bits \ \ \ \ \ \ Range after combining( -,+)54bits}\\\\$ $\textt{-2^{12} from + (2^{12}-1) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -2^{27} from + (2^{27}- 1)}$

$= \frac{24}{2} = 12\\\\= \frac{54}{2} = 27$

The range is accomplished by dividing the bits by 2 into the two sides of the o and the number is one short to 0.

8 0

3 years ago

Technician A states that a tap handle has a right-angled jaw that matches the squared end that all taps have. Technician B state

Elena L [17]

Answer:

Technician A and Technician B are correct

Explanation:

Based on the information provided within the question it can be said that both Technician A and Technician B are correct. A tap handle's right-angled jaw allows many different taps to be attached for different types of situation to more comfortably and conveniently handle that situation. Such as a T-shaped tap in order to cut a thread in an awkward space as Technician B has stated.

3 0

3 years ago