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3 years ago

Find the limit lim 5tan^-1 (ln3x) x>infinity

1 answer:

8 0

Lim ln(3x)=∞ as x->∞
tan^(-1)(∞)=π(k+1/2) where k is an integer.
Therefore
lim 5tan^(-1)(ln(3x))=5(k+1/2)π as x-> ∞ and where k&in;Z (i.e. integers)

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