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rosijanka [135]
3 years ago
11

Show why the following statement is true: 2^−1/2 = 1/2^1/2

Mathematics
1 answer:
Alik [6]3 years ago
6 0

In order to solve a negative exponent, you have to consider the multiplicative inverse of the base:

a^{-m}=\dfrac{1}{a^m}=\left(\dfrac{1}{a}\right)^m

So, if we solve the negative exponent on the left hand side, we have

2^{-\frac{1}{2}}=\dfrac{1}{2^\frac{1}{2}}=\left(\dfrac{1}{2}\right)^{\frac{1}{2}}

which is the right hand side.

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The graph below shows the number of shirts of each color in a store. How many more red shirts than the total number of blue shir
MArishka [77]
The answer is A) 15, Total blue and yellow shirts is 30 were red is 45

45-30=15
4 0
3 years ago
Graph f(x)=3x-1 and g(x)=2^x on the same coordinate plane.
julsineya [31]

Answer:

B. 1 and D. 3.  

Step-by-step explanation:

The figure below shows the graphs of f(x) = 3x - 1 (red) and g(x) = 2^x (blue).

The solutions of 3x - 1 = 2^x are the points at which the two curves intersect.

The solutions are at x = 1 and x = 3.

Check:

3 × 1 - 1 = 2¹     3 × 3 -1 = 2³

    3 - 1 = 2           9 - 1 = 8

        2 = 2                8 = 8

7 0
3 years ago
Jane says that she can use addition to show that the graphs of 2x - 3y = 1 and 2x + 3y = 2 are intersecting lines. In two or mor
iogann1982 [59]
For this case we have the following equations:
 2x - 3y = 1
 2x + 3y = 2
 When adding both equations we observe that:
 Sentence 1: we have an equation of a variable, which in this case will be x. We can clear the value of x.
 Sentence 2: Knowing the value of x, we can substitute in any equation and find the value of y.
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4 0
3 years ago
Which statements are true about the area of the
cupoosta [38]

Answer:

A=bh..I don't get for those numbers

7 0
3 years ago
In triangle ABC, angle A is 75o and angle B is 20o. Select the triangle that is similar to triangle ABC.
Arturiano [62]

Answer:

A. \triangleDEF where \angle D = 75^{\circ} and \angle E = 20^{\circ}.

Step-by-step explanation:

At first we must keep in mind that two triangles are similar when they have same angle configuration, that is, each pair of angles is congruent. If \triangleABC and \triangleDEF, then \angle A \equiv \angle D and \angle B \equiv \angle E. Hence, \angle D = 75^{\circ} and \angle E = 20^{\circ}.

In a nutshell, correct answer is A.

4 0
3 years ago
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