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ANTONII [103]
3 years ago
11

Find the greatest 3 digit perfect square

Mathematics
1 answer:
klio [65]3 years ago
5 0

Answer:

961

Step-by-step explanation:

this is equivalent to(31*31)

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the population of a school is 400 students. Next year it is expected to be about 120% of what it is now. Choose next year's stud
Gelneren [198K]
Given:
this year's population: 400 students
next year's population: 120% of this year's population

this year's population x rate of next year's population = next year's population

400 students * 120% = 480 students  CHOICE D.

There will be 480 students next year.


5 0
3 years ago
I need help, this is geometry
Artemon [7]

Answer:

∠P = 39º

∠Q=120º

∠R = 21º

Step-by-step explanation:

m∠P+m∠Q+m∠R=180º (sum of ∠s in a triangle)

2x-3+6x-6+x=180º (substitution)

9x-9=180º (algebra)

9x=189º (algebra)

x=21º (algebra) (this is ∠R)

(2x-3)=39º (algebra) (this is ∠P)

6x-6=120º (algebra) (this is ∠Q)

7 0
2 years ago
Read 2 more answers
Two dice are rolled. Define the events as follows: A : sum of 7, B : doubles, C : sum of 8
love history [14]

Answer: for a sum of 7 would either be 6 and 1, 5 and 2 or 4 and 3. you can roll a double 1,2,3,4,5,6. the sum of 8 would be 2 and 6, 3 and 5 and a double 4,

Step-by-step explanation:

well the there are six sides on a die so 6 x 2 is 12 so the max sum you can get is 12. So you take 7 and you start adding up to 7, same thing for sum of 8. since there is 6 sides and a pair of dices you will roll six doubles

5 0
2 years ago
Is 1\8 equivalent to 4\32
Klio2033 [76]
Yes it is, 8•3 is 32
4 0
3 years ago
5. 3x + 5y + 5z =1<br> x - 2y = 5<br> 2x + 4y = 11
lilavasa [31]

Answer:

see explanation

Step-by-step explanation:

Given the 3 equations

3x + 5y + 5z = 1 → (1)

x - 2y = 5 → (2)

2x + 4y = 11 → (3)

Use (2) and (3) to solve for x and y

Multiply (2) by 2

2x - 4y = 10 → (4)

Add (3) and (4) term by term

4x = 21 ( divide both sides by 4 )

x = \frac{21}{4\\}

Substitute this value of x into (3)

2 × \frac{21}{4\\} + 4y = 11

\frac{21}{2\\} + 4y = 11 ( subtract \frac{21}{2\\} from both sides )

4y = \frac{1}{2} ( divide both sides by 4 )

y = \frac{1}{8\\}

Substitute the values of x and y into (1) and solve for z

3 × \frac{21}{4\\} + 5 × \frac{1}{8\\} + 5z = 1

\frac{63}{4} + \frac{5}{8} + 5z = 1

\frac{131}{8} + 5z = 1 ( subtract \frac{131}{8} from both sides )

5z = - \frac{123}{8} ( divide both sides by 5 )

z = - \frac{123}{40}

Solution is

x = \frac{21}{4\\}, y = \frac{1}{8\\}, z = - \frac{123}{40}

3 0
2 years ago
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