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noname [10]
3 years ago
7

Assume you have $2,000 in a savings account at the beginning of the year and the price level is equal to 100. If the price level

is equal to 95 at the end of the year, the real value of your savings is closest to
Business
1 answer:
Svetradugi [14.3K]3 years ago
4 0

Answer:

$2105

Explanation:

Given that

Amount of savings = 2000

Price level at beginning = 100

Price level at the end = 95

Recall that

Real value = Amount ÷ (ending period price level ÷ beginning period price level)

Thus,

Real value = 2000 ÷ (95/100)

= 2000 ÷ (0.95)

= $2105.26

Thus, the real value of the savings at year end is $2105

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Which area of study involves microeconomics?
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Answer:

The science of microeconomics covers a variety of specialized areas of study including: Industrial Organization: the entry and exit of firms, innovation, and the role of trademarks. Labor Economics: wages, employment, and labor market dynamics.

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Knox operates an electronics store as sole proprietor. On April 5, Knox was involuntarily petitioned into bankruptcy under the l
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Answer:

$800

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  • <u>Noll will receive $5,000    </u>
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The Digital Millennium Copyright Act, signed in 1998, Multiple Choice allows anyone with access to a computer to publish origina
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2 years ago
A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by upper c equals 0.
Fantom [35]

Answer:

The cost per month is increasing at a rate $365.

Explanation:

Differentiation Formula

  • \frac{d}{dx}(x^n)= nx^{n-1}  
  • \frac{d}{dx}(a)=0             [ where a is a constant]
  • \frac{d}{dx}(ax^n)=a \frac{d}{dx}(x^n)= anx^{n-1}

Given that,

A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by

c=0.2x^2+10,000.

Again given that,

the rate of changing production is 13 unit per month

i.e \frac{dx}{dt}=13

To find the cost per month, we need to find out the value \frac{dc}{dt} when production is changing at the rate 13 units per month and the production is 70 units.

c=0.2x^2+10,000

Differentiating with respect to t

\frac{d}{dt}(c)=\frac{d}{dt}(0.2x^2)+\frac{d}{dx}(10,000)

\Rightarrow \frac{dc}{dt}=0.2\frac{d}{dt}(x^2)+\frac{d}{dx}(10,000)

\Rightarrow \frac{dc}{dt}=0.2\times 2x^{2-1}\frac{dx}{dt}+0

\Rightarrow \frac{dc}{dt}=0.4x\frac{dx}{dt}

Plugging \frac{dx}{dt}=13

\Rightarrow \frac{dc}{dt}=0.4x\times 13

\Rightarrow \frac{dc}{dt}=5.2x

\frac{dc}{dt}|_{x=70}=5.2\times 70 [ plugging x=70]

            =364

[ The unit of c is not given. Assume that the unit of c is dollar.]

The cost per month is increasing at a rate $365.

4 0
3 years ago
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