ANSWER
![(25\times9)+(75\times9)=9(25+75)](https://tex.z-dn.net/?f=%2825%5Ctimes9%29%2B%2875%5Ctimes9%29%3D9%2825%2B75%29)
![(25\times9)+(75\times9)=9(100)](https://tex.z-dn.net/?f=%2825%5Ctimes9%29%2B%2875%5Ctimes9%29%3D9%28100%29)
![(25\times9)+(75\times9)=900](https://tex.z-dn.net/?f=%2825%5Ctimes9%29%2B%2875%5Ctimes9%29%3D900)
EXPLANATION
According to the distributive property,
![(a\times b)+(a\times c)=a(b+c)](https://tex.z-dn.net/?f=%28a%5Ctimes%20b%29%2B%28a%5Ctimes%20c%29%3Da%28b%2Bc%29)
This implies that,
![(25\times9)+(75\times9)=9(25+75)](https://tex.z-dn.net/?f=%2825%5Ctimes9%29%2B%2875%5Ctimes9%29%3D9%2825%2B75%29)
![(25\times9)+(75\times9)=9(100)](https://tex.z-dn.net/?f=%2825%5Ctimes9%29%2B%2875%5Ctimes9%29%3D9%28100%29)
The Right Hand Side of the equation now has 2 factors.
We solve now to obtain;
![(25\times9)+(75\times9)=900](https://tex.z-dn.net/?f=%2825%5Ctimes9%29%2B%2875%5Ctimes9%29%3D900)
Answer:
d=5.39 units
Step-by-step explanation:
Given A (-3, -2)
T= (x+5, y-3)
T= (-3+5, -2-3)
T=(2,-5)
Applying the translation on;
A( -3,-2)
A' (-3+2, -2+ -5)
A'= (-1, -7)
Distance
d= ![\sqrt { X2-X1)^2 + (Y2-Y1)^2](https://tex.z-dn.net/?f=%5Csqrt%20%7B%20X2-X1%29%5E2%20%2B%20%28Y2-Y1%29%5E2)
A = (-3,-2) and A'(-1, -7)
d=√ (-1--3)² + (-7--2)²
d=√ (2)²+(-5)²
d=√4+25
d=√29
d=5.39 units
Answer:
Step-by-step explanation:
Answer:
Option A
Step-by-step explanation:
Number of components assembled by the new employee per day,
N(t) = ![\frac{50t}{t+4}](https://tex.z-dn.net/?f=%5Cfrac%7B50t%7D%7Bt%2B4%7D)
Number of components assembled by the experienced employee per day,
E(t) = ![\frac{70t}{t+3}](https://tex.z-dn.net/?f=%5Cfrac%7B70t%7D%7Bt%2B3%7D)
Difference in number of components assembled per day by experienced ane new employee
D(t)= E(t) - N(t)
D(t) = ![\frac{70t}{t+3}-\frac{50t}{t+4}](https://tex.z-dn.net/?f=%5Cfrac%7B70t%7D%7Bt%2B3%7D-%5Cfrac%7B50t%7D%7Bt%2B4%7D)
= ![\frac{70t(t+4)-50t(t+3)}{(t+3)(t+4)}](https://tex.z-dn.net/?f=%5Cfrac%7B70t%28t%2B4%29-50t%28t%2B3%29%7D%7B%28t%2B3%29%28t%2B4%29%7D)
= ![\frac{70t^2+280t-50t^2-150t}{(t+3)(t+4)}](https://tex.z-dn.net/?f=%5Cfrac%7B70t%5E2%2B280t-50t%5E2-150t%7D%7B%28t%2B3%29%28t%2B4%29%7D)
= ![\frac{20t^2+130t}{(t+3)(t+4)}](https://tex.z-dn.net/?f=%5Cfrac%7B20t%5E2%2B130t%7D%7B%28t%2B3%29%28t%2B4%29%7D)
= ![\frac{10t(2t+13)}{(t+4)(t+3)}](https://tex.z-dn.net/?f=%5Cfrac%7B10t%282t%2B13%29%7D%7B%28t%2B4%29%28t%2B3%29%7D)
Therefore, Option A will be the answer.