The complete question is
A fence must be built to enclose a rectangular area of 5000ft^2. Fencing material costs $1 per foot for the two sides facing north and south and 2$ per foot for the other two sides. Find the cost of the least expensive fence.
Answer:
Total cost will be $400
Step-by-step explanation:
Let x = be other side
y = north and south side
Area = x*y = 5000
Perimeter of the rectangle = 2x + 2y
cost of fencing = 2(1)*5000/x + 2*2x
= 10000/x + 4x
now to get the least we will take the derivative of this
C'(x) = 10000(-1/x^2) + 4 =0
x^2 = 2500
x= 50ft cost = 2*$2*50 = $200
y= 100ft cost = 2*$1*100 = $200
Total cost = $400
Answer:
3/2
Step-by-step explanation:
We can use the slope formula to find the slope of the line
m = ( y2-y1)/(x2-x1)
Using the points (0,-4) and (2,-1)
m = ( -1 - -4)/( 2 - 0)
= (-1+4)/ (2 -0)
= 3/2
The value of dy/dx for the functions are
(i) 
(ii) 
<h3>Differentiation</h3>
From the question, we are to determine dy/dx for the given functions
(i) 
Let 
and

Also,
Let 
∴ 
First, we will determine 
Using the Chain rule


∴ 
Also,

∴ 
Thus,



Now, using the product rule

From above

∴ 
Now,


(ii) 
Then,







Hence, the value of dy/dx for the functions are
(i) 
(ii) 
Learn more on Differentiation here: brainly.com/question/24024883
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3p - 7 + p = 13
3p + p = 13 + 7
4p = 20
p = 20 : 4
p = 5
Answer:
look it up
Step-by-step explanation: