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Gnesinka [82]
3 years ago
13

Solve for x must show work 5-2x=3

Mathematics
2 answers:
inna [77]3 years ago
6 0
5-2x=3

move the 5 over and subtract form 3

-2x=-2

then divide x by the other number to find that x=1





3.   8x-5=2x+25
      
move the 5 over to the right side and add it to 25, and take 2x and subract it from 8x

6x=30

now you divide

x=5
Nana76 [90]3 years ago
6 0
On number one:
5 - 2x = 3
-2x = 3 - 5
-2x = -2 (divide both sides by -2 to get x)
-2x/(-2) = -2/(-2)
x = 1


On the second one:
<span>
Simplifying 2(x + 1) = 9
Reorder the terms: 2(1 + x) = 9
(1 * 2 + x * 2) = 9
(2 + 2x) = 9
</span>
<span>Solving 2 + 2x = 9
Solving for variable 'x'.
</span>
<span>Move all terms containing x to the left, all other terms to the right.
Add '-2' to each side of the equation.
2 + -2 + 2x = 9 + -2
</span>
<span>Combine like terms: 2 + -2 = 0
0 + 2x = 9 + -2
2x = 9 + -2
</span>
<span>Combine like terms: 9 + -2 = 7
2x = 7
</span>
<span>Divide each side by '2'.
x = 3.5

Simplifying x = 3.5

On the Third problem:
</span>
<span>Simplifying 8x + -5 = 2x + 25
Reorder the terms: -5 + 8x = 2x + 25
Reorder the terms: -5 + 8x = 25 + 2x
</span>
<span>Solving -5 + 8x = 25 + 2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
</span>
<span>Add '-2x' to each side of the equation. -5 + 8x + -2x = 25 + 2x + -2x 
Combine like terms: 8x + -2x = 6x -5 + 6x = 25 + 2x + -2x
</span>
<span>Combine like terms: 2x + -2x = 0
-5 + 6x = 25 + 0 -5 + 6x = 25
</span>
<span>Add '5' to each side of the equation. -5 + 5 + 6x = 25 + 5
Combine like terms: -5 + 5 = 0
0 + 6x = 25 + 5
6x = 25 + 5
</span>
<span>Combine like terms: 25 + 5 = 30
 6x = 30
Divide each side by '6'. x = 5
Simplifying x = 5

Problem 1 (x) equals 1
Problem 2 (x) equals 3.5
Problem 3 (x) equals 5

Hope I helped you today

</span>
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Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE <em>RATE</em><em> </em><em>OF</em><em> </em><em>CHANGES</em><em> </em>[<em>SLOPES</em>], so 1 2⁄5 [or 7⁄5] becomes −5⁄7.

I am joyous to assist you anytime.

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