Answer: The third quartile of the distribution is 23.
Step-by-step explanation:
First we write the data in ascending order:
4,5,8,10, 11,11, 13,15,16, 18, 18, 18, 21, 23, 24, 24, 25, 27, 31, 32
Since there are 20 terms:
First half is for First Quartile :
4,5,8,10, 11,11, 13,15,16, 18
Second half is for third Quartile:
18, 18, 21, 23, 24, 24, 25, 27, 31, 32.
So, Value of third quartile would be
Hence, the third quartile of the distribution is 23.
Answer:
Yes, there is sufficient evidence to support the claim that the mean cost is $1.
Step-by-step explanation:
Data Given:
The population standard deviation = $0.2
The sample mean cost = $0.93
The sample size n = 12
From above we can use the Z-test for testing the mean from the above given data.
To check whether the mean cost of newspaper is $1.00
:
= $1
:
$1
The test statistics Z =
Z =
Z = -1.212
The P-value = 2P (Z< - 1.212)
= 2 × 0.1128
= 0.2256
Since the value of P is more than the significance level; do not reject the
Conclusion: We therefore conclude that there is sufficient evidence to support the claim that the mean cost is $1.
