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3 years ago

Are geologic structures like folds and faults in any way related to plate tectonic processes? Explain.

Geography

1 answer:

xxTIMURxx [149]3 years ago

7 0

Answer:

<u>Yes , They are architectural structures that shape the geology of earth.</u>

Explanation:

These geologic structures influence the shape and size of landscape development and determine the degrees to landscape hazards. Folds and faults and other geologic structures accommodate large forces/stress on earth's tectonic plates.

Foldes are of two types such as Syncline and Anticline. Formed due to the crustal bending and wrapping of the geo sediments or rocks. The youngest at the top and the oldest at the bottom. As antiforms contain comparatively younger folded rock strata.

Faults are a planar surface within the earth, where the rocks have slid or broken a fault may be caused due to the elastic strains on the rocks, the rocks on either side are shifted in opposite direction and the faults get induced.

There are many types of faults and folds in the history of the earth's surface, many of these have led to the formation or shaping of mountain ranges and various mountain chains.
Another example can be of Mount Everest which is a young folded mountain formed from the colloid of the Tethys sea when India was once a part of the Australian continent.

Plate tectonics is thus directly related to the formation and motion of the plates which mover the entire planet and shape its orogeny

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Legislative and judicial

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3 years ago

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monitta

At first you have to write the variables out which are
$3x + 2y + 5x + 3y$
now you have to combine like terms
$3x + 5x = 8x$
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3 years ago

Find an equation for the perpendicular bisector of the line segment whose endpoints

zzz [600]

Answer:

y= -7/2x-26/2 or y= -7/2x-13

Explanation:

To solve this question you need all of these formulas:

gradient: $\frac{y2-y1}{x2-x1}$ , Point-Slope $y-y1=m(x-x1)$ ,

perpendicular m $(m1)x(m2)=-1$ , Midpoint $(\frac{x1+x2}{2}$ , $\frac{y1+y2}{2} )$

and equation of a line $y=mx+c$

where m stands for gradient

First things first.

To start you have to know the data of the line that includes the two endpoints, so you calculate its gradient (m) of this line with the gradient fromula: $m=\frac{-4-(-8)}{5-(-9)}$ , which equals 4/14 or 2/7

(It can also be called rise/run) (Remember the rule of signs where - and - equal +)

with that information you can proceed with the point-slope or point-gradient formula, so you plug the values: y-(-8) = 2/7 (x-(-9)), which results in y+8=2/7(x+9) and then y+8=2/7x+18/7.

To finish the equation you move eight to the other side. To simplify things you can change it into a fraction as I did, and remember to change signs.

y=2/7x+18/7 -8 -> y=2/7x+18/7-56/7 . This gives us the number of y=2/7x-38/7, which is the equation of the first line.

Now to know the gradient of the second line you apply the formula of perpendicular bisector where m1 x m2 = -1. We know m1 (gradient of the first line) is 2/7, so m2 = $\frac{-1}{2/7}$ = -7/2. m2 is therefore -7/2

Now you have to know the midpoint between the two endpoints, which will act as the start point of the perpendicular bisector

M (midpoint) = $(\frac{-9+5}{2} ,$ $\frac{8+(-4)}{2} )$ , which give us the coordinates of (-2, -6)

(remember, x coordinate is always first)

with this point we can apply again the point-slope formula to know the equation of the line:

y-(-6)=-7/2(x-(-2)) -> y+6=-7/2(x+2) -> y+6=-7/2x - 14/2

Move the 6 to isolate the y

y=-7/2x -14/2 - 12/2

which equals y= -7/2x -26/2

You can check the results in this page: GraphPlotter

https://www.transum.org/Maths/Activity/Graph/Desmos.asp

To make sure the answer is correct.

Hope it helps :)

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2 years ago

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Serhud [2]

La respuesta correcta a esta pregunta abierta es la siguiente.

Las diferentes ramas industriales son las siguientes. Primero, lo que se conoce como la industria básica. Luego, la industria manufacturera y la industria de la transformación. Cuando hablamos de la industria básica estamos hablando de las empresas que se encargan de extraer la materia prima y los recursos naturales, como lo hacen las empresas petroquímicas o las que extraes los metales y minerales de la tierra. Cuando se han extraído los materiales, se mandan a fábricas para que los transformen en productos. Ahí es donde entra la industria de la transformación, que convierte los recursos naturales en textiles. Finalmente la industria manufacturera fabrica la ropa que nos ponemos todos los días. O cualquier otro producto de consumo público.

La importancia de estas industrias es que son vitales para la vida económica de un país. Si no existieran, no habría forma de transformar la materia prima o recursos naturales en los productos que usamos todos los días.

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Explanation:

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