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3 years ago

When x=1/2, what is the value of 8x-3 over x?

Mathematics

1 answer:

Taya2010 [7]3 years ago

5 0

$\frac{8( \frac{1}{2}) - 3 } { \frac{1}{2} }$
$\frac{(8 \times \frac{1}{2}) - 3 }{ \frac{1}{2} } = \frac{4 - 3}{ \frac{1}{2} }$
Because half of 8 is 4

$\frac{1}{ \frac{1}{2} } = \frac{1 \times 2}{1 \times 1} = 2$
Divide 1 by 1/2 or .5... 1 becomes 1/1 and 1/2 is flipped to 2/1, then multiply

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Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

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Now

${: \implies \quad \sf T_{3}= T_{1}+(3-1)d}$

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${: \implies \quad \sf T_{3}= 8-6}$

${: \implies \quad \bf \therefore \: T_{3}= 2}$

Also ,

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${: \implies \quad \sf T_{4}= 8-9}$

${: \implies \quad \bf \therefore \: T_{4}= -1}$

Now , The given table can be written as ;

${\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}$

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

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