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enyata [817]
3 years ago
12

What are the x and y-intercepts of the line described by the equation? 3x−9y=10.8

Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0

3x-9y=10.8\\\\x-intercept\ for\ y=0:\\\\3x-9(0)=10.8\\\\3x-0=10.8\\\\3x=10.8\qquad\text{divide both sides by 3}\\\\\boxed{x=3.6\to(3.6,\ 0)}\\\\y-intercept\ for\ x=0:\\\\3(0)-9y=10.8\\\\0-9y=10.8\\\\-9y=10.8\qquad\text{divide both sides by (-9)}\\\\\boxed{y=-1.2\to(0,\ -1.2)}

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Over which interval are the exponential and linear function approximately the same?
quester [9]

hard to tell but from 0.75 to 1

7 0
2 years ago
What makes 2.4=6x true?
Murrr4er [49]
2.4=6x so isolated the variable, 2.4/6=0.4 so x=0.4
4 0
3 years ago
Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

4 0
4 years ago
Read 2 more answers
This should be easy to answer with a calculator but I don’t really have a calculator on hand lol so please solve it for me:
GuDViN [60]

Answer:

- 132

Step-by-step explanation:

This can be evaluated without a calculator.

Take each part of the calculation and evaluate, that is

- 6(3)(- 4) = - 6 × - 12 = 72

3(3)²(- 4) = 3 × 9 × - 4 = - 12 × 9 = - 108

2(3)(- 4)² = 6 × 16 = 96

Putting the 3 parts back together

72 - 108 - 96

= 72 - 204

= - 132

6 0
3 years ago
Expand -5k^2(k^2-4k)
lawyer [7]

How to solve your problem

5

2

(

2

−

4

)

5k^{2}(k^{2}-4k)

5k2(k2−4k)

Simplify

1

Distribute

5

2

(

2

−

4

)

{\color{#c92786}{5k^{2}(k^{2}-4k)}}

5k2(k2−4k)

5

4

−

2

0

3

{\color{#c92786}{5k^{4}-20k^{3}}}

5k4−20k3

Solution

5

4

−

2

0

3

3 0
3 years ago
Read 2 more answers
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