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3 years ago

Calculus question....does anyone know how to solve this?

Mathematics

1 answer:

iogann1982 [59]3 years ago

6 0

$h(x)=(f\circ g)(x)$
$\sqrt{x+5}=\sqrt{g(x)+2}$
$x+5=g(x)+2$
$g(x)=x+3$

Just to check this is correct:

$(f\circ g)(x)=f(g(x))=f(x+3)=\sqrt{(x+3)+2}=\sqrt{x+5}=h(x)$

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