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3 years ago

11

Are the polygons similar? If they are, write a similarity statement and give the scale factor. The figures are not drawn to scal

e.

1 answer:

Luba_88 [7]3 years ago

8 0

Answer:no

Step-by-step explanation:

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An online store sells specialty bags. They charge $8 for shipping and $21 per bag ordered.

stellarik [79]

Answer:

cool

Step-by-step explanation:

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3 years ago

A=1/2•e•m <br> solve the following formula for e

Vedmedyk [2.9K]

(1 / 2) x e x meters =

1.35914091 meters

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3 years ago

Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t

Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

$(AO)^2=(AD)^2-(DO)^2$

$x^{2}=5^2-3^2$

$x^{2}=25-9$

$x^{2}=16$

Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

$x=\pm 4$

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

$(OC)^2=(DC)^2-(DO)^2$

Upon substituting our given values we will get,

$y^2=10^2-3^2$

$y^2=100-9$

$y^2=91$

Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$

$\text{The length of the longer diagonal}=4+9.54$

$\text{The length of the longer diagonal}=13.54$

Therefore, the length of longer diagonal is approximately 13.54 inches.

3 0

3 years ago

What is the coordinate if (2,2) is reflected over x=2

luda_lava [24]

Answer:

2,-2

Step-by-step explanation:

Its pretty simple, all you have to do is find opposite of y and put it.

8 0

3 years ago

1) Mister Smith wants to put a small fence around his garden. A store sells three feet sections of fence at cost of $5.49 per se

Gelneren [198K]

1. Mister Smith spends $145 total. The number of sections is$ 145/$ 5.49 = 26.41 ~ 27 sectionsThe length of the fence is27 (3) = 81 feet
2. Let x be the number of students in each class. The inequality is0.5x + 4 > 7.25
3. D) 38<=B<=48
4. C) 6<=M<=85
5. B) M+H<=10,4M+7H<90

5 0

3 years ago