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4 years ago

9

The jade restaurant has a large aquarium on display in its lobby.The base of the aquarium is 5 feet by 2 feet and the height is

4 feet. How many cubic feet of water are needed to completely fill the aquarium?

1 answer:

forsale [732]4 years ago

6 0

40 cubic ft of water are needed to completely fill the aquarium. I did it right this time. ;)

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PLEASE PLEASE PLEASE HELP I NEED IT <br><br> What is the sum of the series?

JulsSmile [24]

Formula :

$n\left(a_1+\frac{d\left(n-1\right)}{2}\right)$

Plug in the values :

$20\left(1+\frac{-3\left(20-1\right)}{2}\right) = 550$

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Answer:550
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4 years ago

If 2 objects cost 40 dollars how much would 7 objets cost?

arlik [135]

Answer:

140

Step-by-step explanation: 20X7=140

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4 years ago

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Given that the hypotenuse of this right triangle is 25 cm long and that tan(θ) = 3find the values of x and y, accurate to the ne

lara31 [8.8K]

The tangent of an angle is the opposite side divided by the adjacent side of the triangle, relative to the angle. By tan theta = 3, it means that, the adjacent side is thrice as long as the opposite side.

3a = o

Then, using Pythagorean's theorem:

25² = a² + o²
Substituting o,
25² = a² + (3a)²
25² = a² + 9a²
25² = 10a²
a = 7.9 cm

Then, 3(7.9) = o = 23.7 cm

So, the opposite side is 23.7 cm and the adjacent side is 7.9 cm.

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3 years ago

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Cos(−θ)=√3/3, sinθ<0

Delicious77 [7]

Answer:

$\sin\theta=-\frac{\sqrt{6}}{3}$

Step-by-step explanation:

The given trigonometric equation is $\cos(-\theta)=\frac{\sqrt{3} }{3}$ .

We can either use the Pythagorean identity or the right angle triangle to solve for $\sin\theta$ .

According to the Pythagorean identity,

$\cos^2\theta+\sin^2\theta=1$

Recall that, the cosine function is an even function, therefore

$\cos(-\theta)=\cos(\theta)$

$\Rightarrow \cos(\theta)=\frac{\sqrt{3} }{3}$ .

We substitute this value in to the above Pythagorean identity to get;

$(\frac{\sqrt{3}}{3})^2+\sin^2\theta=1$

$\Rightarrow \frac{3}{9}+\sin^2\theta=1$

$\Rightarrow \sin^2\theta=1-\frac{3}{9}$

$\Rightarrow \sin^2\theta=\frac{6}{9}$

$\Rightarrow \sin\theta=\pm \sqrt{\frac{6}{9}}$

$\Rightarrow \sin\theta=\pm \frac{\sqrt{6}}{3}$

But we were given that,

$\sin\theta\:$ , so we choose the negative value.

$\Rightarrow \sin\theta=-\frac{\sqrt{6}}{3}$

The correct answer is B

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4 years ago

Free 25 points TwT..

DerKrebs [107]

Answer: hmmmmmmmm sol and hmmmmmmm lemme think and charger?

Step-by-step explanation:

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3 years ago

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