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4 years ago

Help!!i never learned this!!

Mathematics

1 answer:

guapka [62]4 years ago

7 0

Half the class (i.e. s * 1/2) would be less than or equal to 17:
$\frac{s}{2} \leq 17$

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The window frame is a regular octagon. It is made from eight pieces of wood shaped like congruent isosceles trapezoids . What ar

scoray [572]

Answer:

∠A= 112.5°, ∠B=67.5°, ∠C is 67.5° and ∠D 112.5°.

Step-by-step explanation:

Consider the provided information.

The sum of all interior angle of a polygon is: $(n-2)180$

Substitute n = 8.

$(8-2)180=1080$

Thus, the measure of each angle is: $\frac{1080}{8}=135$

∠B and ∠C are congruent and their sum is 135°

∠B+∠C=135°

∠B=67.5°

Hence, the m angle B and m angle C is 67.5°.

The sum of all angles of a quadrilateral is 360°.

∠A+∠D+∠B+∠C=360°

∠A+∠D=360°-135°

∠A+∠D=225°

∠A and ∠D are congruent and their sum is 225°

∠A+∠D=225°

∠A=∠D=112.5°

Hence, the m angle A and m angle D is 112.5°.

8 0

4 years ago

The area, A, of a square with a side of length x is given by A = x^2? Use this relationship to verify that doubling the length o

amid [387]

Answer:

Step-by-step explanation:

5 0

3 years ago

What is the solution to this matrix equation?

dimulka [17.4K]

Answer:

Step-by-step explanation:

Go to Khan Academy and type in Solving linear systems the matrices (video).

8 0

3 years ago

4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

6 0

4 years ago

THERE ARE 165 CHILDREN TAKING SWIMMING LESSONS AT THE POOL IF 10 CHILDREN WILL BE ASSIGNED TO EACH INSTRUCTORS NEED TO BE HIRED?

N76 [4]

Answer:

Step-by-step explanation:

165/10=16.5 17 because the extra 5 students need a teacher !

4 0

3 years ago

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