Question

show all work to multiply 3 plus the square root of negative 16 times 6 minus the square root of negative 64

Answer 1

Answer:

$\Huge \boxed{3+16i}$

$\rule[225]{225}{2}$

Step-by-step explanation:

$3+\sqrt{-16} * 6-\sqrt{-64}$

Using imaginary number rule : $\sqrt{-n} =\sqrt{n} *i$

Where $n$ is a positive integer.

$3+\sqrt{16} *i* 6-\sqrt{64}*i$

$3+4i* 6-8i$

Multiplying.

$3+24i-8i$

Combining like terms.

$3+16i$

$\rule[225]{225}{2}$

Answer 2

Answer:

3 + 16i

Step-by-step explanation:

3 + √-16 * 6 - √-64

= √-16 * 6 = 24i;    √-16 * 6;     √-16 = 4i

= 4 * 6i    multiply the numbers 4 * 6 = 24

= 24 i

√-64 = 8i;   √64    apply a radical rule

= √-1 √64

= √64  i;    √64 = 8

= 8i

= 3 + 24i - 8i

= 3 + 16i