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Sergeu [11.5K]
3 years ago
6

20 POINTS ASAP 15552 in fraction form

Mathematics
2 answers:
denis-greek [22]3 years ago
7 0
Is there a decimal in that number?
Komok [63]3 years ago
3 0
Any decimals in the number or is 15552 the whole number
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if $5,000,000 isinvested at 4% interest compunded continuously, how much willl the investment be worth in 30 years
Katarina [22]
The answer is $16216987.55 (IMPORTANT: This is the answer assuming that the interest rate is annually. The quesiton says 'continuously' so I was a bit confused)

To solve this problem, you can use the compound interest formula. 

Here it is once you plug in the numbers: A = 5,000,000 ( 1 + .04) ^30

Just solve the equation to find the solution.


8 0
3 years ago
What are the zeros of the function
aleksklad [387]

Answer:

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Description

DescriptionIn mathematics, a zero of a real-, complex-, or generally vector-valued function, is a member of the domain of such that vanishes at; that is, the function attains the value of 0 at, or equivalently, is the solution to the equation. A "zero" of a function is thus an input value that produces an output of

4 0
3 years ago
Please help fast please
victus00 [196]

Answer:

A not similar

Step-by-step explanation:

72 × 2 = 144

78 × 2 = 156

7 0
3 years ago
PLEASE PLEASE HELPPP !!
Shalnov [3]
F since its a 90-45-45
3 0
3 years ago
A tank contains 250 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
VashaNatasha [74]

Answer:

A(t)=250-210e^{-\frac{t}{50}}

Step-by-step explanation:

We are given that

Volume,V=250 L

Mass of salt=m=40 g

Brine containing 1 g per liter

Pumped into the tank at the rate=5 L/min

We have to find the number A(t) of grams of salt in the tank at time t.

Rate of change of salt in the tank

\frac{dA}{dt}=Rate in-Rate out

Rate in=5 L/min

Rate out=\frac{A}{250}\times 5=\frac{A}{50} L/min

\frac{dA}{dt}=5-\frac{A}{50}=\frac{250-A}{50}

\int \frac{50dA}{250-A}=\int dt

-50ln(250-A)=t+C

Using the formula

\int \frac{dx}{x}=ln x

A=40 and t=0

-50ln(250-40)=0+C

-50ln(210)=C

Substitute the value

-50ln(250-A)=t-50ln(210)

-50ln(250-A)+50ln(210)=t

50ln\frac{210}{250-A}=t

t=50ln\frac{210}{250-A}

\frac{t}{50}=ln\frac{210}{250-A}

\frac{210}{250-A}=e^{\frac{t}{50}

\frac{250-A}{210}=e^{-\frac{t}{50}}

250-A=210e^{-\frac{t}{50}}

A(t)=250-210e^{-\frac{t}{50}}

8 0
4 years ago
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