Evaluate 2x^2-3x+6 for x=4
2 answers:
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Answer:
- attached graph
- Horizontal Asymptote: y = 5
- twon whole number points are (4,4) and (5,1)
Step-by-step explanation:
- Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote
y = -4^(x-4) + 5
= -4^(4-4) + 5
= -4^(0) + 5
= -1 + 5
= 4
y = -4^(x-4) + 5
= -4^(5-4) + 5
= -4^(1) + 5
= -4 + 5
= 1
