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Lorico [155]
3 years ago
8

Sole the given inequality and graph it on the number line. -2x - 5 < 3​

Mathematics
1 answer:
Anon25 [30]3 years ago
6 0

Answer:

your answer would be X>-4

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Diego's bank granted him
DanielleElmas [232]

Answer:

$72500

Step-by-step explanation:

$72500

5 0
2 years ago
Area of irregular figures<br><br> uhmmm
Ann [662]

Answer:

146

Step-by-step explanation:

4×12+5×10+4×12=146

3 0
3 years ago
Using the quadratic formula to solve 7x2 – x = 7, what are the values of x?
Kruka [31]
How the quadratic formula works:

For any quadratic equation ax² + bx + c = 0, the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

In the case of our equation 7x² - x = 7, first we need to subtract 7 from each side so that we have 0 on the right.
7x² - x - 7 = 0

Identify the values of a, b, and c.
a = 7, b = -1, and c = -7.

Plug these into our quadratic formula and solve.

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(7)(-7)}}{2(7)}=\boxed{\frac{1\pm\sqrt{197}}{14}

There are two values for x: (1+√197)/14 and (1-√197)/14.
The approximate values for these are 1.073976 and -0.931119.
5 0
4 years ago
Read 2 more answers
Quick! Find the results of the given vector subtractions for u = &lt;-8, 4&gt; and v = &lt;2, 7&gt;.
Jobisdone [24]

Subtract corresponding x and y components

- u - v = - <- 8, 4> - <2, 7> = <8, - 4> - <2, 7> = <8 - 2, - 4 - 7> = <6, - 11>

u - v = <- 8, 4> - <2, 7> = <- 8 - 2, 4 - 7> = <- 10, - 3>

v - u = <2, 7> - <- 8, 4> = <2 + 8, 7 - 4> = <10, 3>



8 0
3 years ago
What is the area of a sector with a central angle of (2pi/3) radians and a diameter of 12 in?
Stels [109]

Answer:

The area of the sector is 37.68\ in^{2}

Step-by-step explanation:

step 1

Find the area of the circle

The area of the circle is equal to

A=\pi r^{2}

we have

r=12/2=6\ in ----> the radius is half the diameter

substitute

A=(3.14)(6)^{2}

A=113.04\ in^{2}

step 2

Find the area of a sector with a central angle of (2pi/3)

Remember that

The area of 113.04\ in^{2} subtends a central angle of 2\pi \ radians

so

by proportion

Let

x----> the area of the sector

\frac{2\pi}{113.04}=\frac{(2\pi/3)}{x}\\ \\x=113.04*(2\pi/3)/(2\pi)\\ \\x=37.68\ in^{2}

8 0
3 years ago
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