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AleksandrR [38]
3 years ago
8

SOMEONE PLEASE HELP ME ASAP PLEASE!!!​

Mathematics
2 answers:
marusya05 [52]3 years ago
4 0

Answer:

5/6 and 6/7

Step-by-step explanation:

In the top of the fraction its going up by one each time (1,2,3,4 so the 5 and 6 would be the top half of the fraction), and in the bottom half its also going up by one but it started at 2 so its one more than the top half  (2,3,4,5, so the 6 and 7 would be the bottom half of the fraction)

lyudmila [28]3 years ago
4 0

Answer:

<h3><em>next</em><em> </em><em>two</em><em> </em><em>terms</em></h3>

<em>=</em>

<em>\frac{5}{6}  ,\frac{6}{7}</em>

<em>sol</em><em>ution</em><em>,</em>

<em>here</em><em>,</em>

<em>Top</em><em> </em><em>numbers </em><em>are</em><em> </em><em>increasing</em><em> </em><em>by</em><em> </em><em>1</em>

<em>Bottom</em><em> </em><em>numbers </em><em>are </em><em>also</em><em> </em><em>increasing</em><em> </em><em>by</em><em> </em><em>1</em><em>.</em>

<em>\frac{1}{2} , \frac{2}{3}  ,\frac{3}{4} , \frac{4}{5} , \frac{4 + 1 }{5 + 1}  =  \frac{5}{6} , \frac{5 + 1}{6 + 1}  =  \frac{6}{7}</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>

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Answer:

a)- Given that a student is a 10th grader, there is a 14% chance he or she has a job.

Step-by-step explanation:

Option (a) is correct here because Relative frequency means the probability of occurrence or number of time-specific event occurs to the total event.

Option (b) is not correct because We already know that student is in 10th or 11th grade, after that we get to know about 14% chance.

Option (c) & (d) are clearly not possible.

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Answer:

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Step-by-step explanation:

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3 years ago
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navik [9.2K]

Answer:

Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Step-by-step explanation:

<u>Step 1:  Multiply</u>

<u />(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\

(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}

(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x}  )

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Answer:  Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

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3 years ago
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Calculate the value of 3x + 4y when x = -6 and y = 5.
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Answer:

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joja [24]

The x-values are the heartbeat(s) and the y-values are the time(s)

<h3>How to determine the x and y values?</h3>

The variables are given as:

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As a general rule, the action that is being done is the independent variable.

The action here is the heartbeat.

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So, the ordered pair is (100,60)

When represented as ratio, we have;

Ratio = 60/100

Simplify

Ratio = 0.6 heartbeat per second

Read more about ordered pairs at:

brainly.com/question/8406931

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