Answer:
![[11.5-(2.5*3)]^2=16](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D16)
Step-by-step explanation:
We want to evaluate ![[11.5-(2.5*3)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2)
Let us evaluate within the parenthesis first:
![[11.5-(2.5*3)]^2=[11.5-(7.5)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-%287.5%29%5D%5E2)
![\implies [11.5-(2.5*3)]^2=[11.5-7.5]^2](https://tex.z-dn.net/?f=%5Cimplies%20%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-7.5%5D%5E2)
We again subtract within the bracket to obtain:
![[11.5-(2.5*3)]^2=[4]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B4%5D%5E2)
This finally gives us:
![[11.5-(2.5*3)]^2=16](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D16)
Try this option:
the rule: if f(-x)=f(x), then the function f(x) is even, if f(-x)=-f(x) then the function is odd.
1. f(x)=-5x⁴-2;
if to substitute x→(-x), then f(-x)=-5*(-x)⁴-2; ⇔ f(-x)=-5x⁴-2, in other words f(x)=f(-x), it means that this function is even.
2. f(x)=x³+2x.
if to substitute x→(-x), then f(-x)=(-x)³+2*(-x); ⇔ f(-x)=-(x³+2x), in other words f(-x)=-f(x), it means that this function is odd.
Is there any other information given on this?
Answer:
8
Step-by-step explanation:
Recall the formula for the population mean of a data set:

We already know that μ is 6 and the sum is 48. Substitute:

Divide both sides by 48:

Reciprocal of both sides:

Thus, there are 8 scores in the population size.
And we're done!
3. 152 i think that is it