This is my work. Also 2/3 is a repeating decimal so it’s actually 0.6...
4/3 in simplest form is 4/3 but in decimal form it would be 1.33333
hope this helped, please mark brainilest :)
In the given equation, as the value of <em>y</em> increase, the value of <em>x</em> also
increases.
- Yes, 4·y = 16·x is a direct variation
Reasons:
A direct variation is a relationship that exists between two variables. It is
also known as a direct proportion which can be expressed as; y = k·x
Where <em>k</em> is a number
The given equation is 4·y = 16·x
Dividing both sides by 4 gives;

Which gives;
y = 4·x
Comparing the above equation with the equation for a direct variation gives;
y = 4·x
y = k·x
Therefore;
k = 4
The equation, y = 4·x, and therefore, the equation from which it is derived, 4·y = 16·x, is a direct variation.
Learn more about direct variation here:
brainly.com/question/6499629
Step-by-step explanation:




Step-by-step explanation:
y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1
dy/dx = 12√x
Arc length is:
s = ∫ ds
s = ∫₀¹ √(1 + (dy/dx)²) dx
s = ∫₀¹ √(1 + (12√x)²) dx
s = ∫₀¹ √(1 + 144x) dx
If u = 1 + 144x, then du = 144 dx.
s = 1/144 ∫ √u du
s = 1/144 (⅔ u^(³/₂))
s = 1/216 u^(³/₂)
Substitute back:
s = 1/216 (1 + 144x)^(³/₂)
Evaluate between x=0 and x=1.
s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]
s = 1/216 (145)^(³/₂) − 1/216
s = (145√145 − 1) / 216