1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
leonid [27]
4 years ago
8

A point (-7, -6) is rotated counterclockwise about the origin to map onto (-6, 7). The

Mathematics
1 answer:
Ierofanga [76]4 years ago
3 0

Option D, 270 is the answer

You might be interested in
Find the area of a triangle
schepotkina [342]

Answer:

  154 cm^2

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh

A = 1/2 (22) * 14

  154 cm^2

8 0
3 years ago
Read 2 more answers
17 pointsss!!!!!!! What makes the equation 3(x-6)=8x-3(3x+7 true
almond37 [142]

Answer:

C (-3/4)

Step-by-step explanation:

Decimal form is - 0.75

6 0
3 years ago
PLease NEED HELP! thank you
adelina 88 [10]
.32 is the answer to this question
7 0
3 years ago
Easy Question! Just solve with given calculator!
notsponge [240]
1.f=x2+4                                                                                                                      --------
     4x2+3x

i dont know the second one sorry
5 0
3 years ago
Determine whether each expression below is always, sometimes, or never equivalent to sin x when 0° < x < 90° ? Can someone
Lubov Fominskaja [6]

Answer:

(a)\ \cos(180 - x) --- Never true

(b)\ \cos(90 -x) --- Always true

(c)\ \cos(x) ---- Sometimes true

(d)\ \cos(2x) ---- Sometimes true

Step-by-step explanation:

Given

\sin(x )

Required

Determine if the following expression is always, sometimes of never true

(a)\ \cos(180 - x)

Expand using cosine rule

\cos(180 - x) = \cos(180)\cos(x) + \sin(180)\sin(x)

\cos(180) = -1\ \ \sin(180) =0

So, we have:

\cos(180 - x) = -1*\cos(x) + 0*\sin(x)

\cos(180 - x) = -\cos(x) + 0

\cos(180 - x) = -\cos(x)

-\cos(x) \ne \sin(x)

Hence: (a) is never true

(b)\ \cos(90 -x)

Expand using cosine rule

\cos(90 -x) = \cos(90)\cos(x) + \sin(90)\sin(x)

\cos(90) = 0\ \ \sin(90) =1

So, we have:

\cos(90 -x) = 0*\cos(x) + 1*\sin(x)

\cos(90 -x) = 0+ \sin(x)

\cos(90 -x) = \sin(x)

Hence: (b) is always true

(c)\ \cos(x)

If

\sin(x) = \cos(x)

Then:

x + x = 90

2x = 90

Divide both sides by 2

x = 45

(c) is only true for x = 45

Hence: (c) is sometimes true

(d)\ \cos(2x)

If

\sin(x) = \cos(2x)

Then:

x + 2x = 90

3x = 90

Divide both sides by 2

x = 30

(d) is only true for x = 30

Hence: (d) is sometimes true

8 0
3 years ago
Other questions:
  • XY is the perpendicular bisector of JK. which of the following statements must be true? check all that apply?
    15·2 answers
  • A number decreased by 5 is 50
    6·1 answer
  • Simplify the expression below. 6n^2 - 5n^2 + 7n^2 6n^2 - 5n^2 = 1n^2 + 7n^2 =8n^2 Is this right?
    12·1 answer
  • A) Antoine's family is taking a summer vacation through the northern united states on day one of the trips the family will be tr
    5·1 answer
  • In the function p(x)= 1/2x-3 what is the domain and range please help thanks !!!!
    15·1 answer
  • Help! is due today please
    15·1 answer
  • Help this is due today
    6·2 answers
  • Work out the median for each group of numbers.
    13·2 answers
  • Help need to know the cross section shape
    6·1 answer
  • what is the area, measured in square centimeters, of the triangle below? Do not include units in your answer
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!