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galina1969 [7]
3 years ago
8

Suppose you crossed a heterozygous yellow pea plant (Yy) with a homozygous green pea plant (yy). What are the possible genotypes

and phenotypes of the offspring? Use the Punnett square in Figure 5-1 to compute your answers. 650-02-01-02-00_files/i0290000.jpg
Biology
2 answers:
spayn [35]3 years ago
7 0

The potential genotypes and phenotypes of the offspring is. Yy, Yy, yy, and yy.

jeka943 years ago
3 0
The possible genotypes and phenotypes for the offspring are:

Yy
Yy
yy
yy
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Select the four statements that are true. Select the four statements that are true.
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Answer: Based on the equation for Hardy-Weinberg equilibrium, the expected number of wolves with the FBFW genotype is 96.

Based on the equation for Hardy-Weinberg equilibrium, the expected number of wolves with the FBFB genotype is 12.

The population may be evolving because the actual number of individuals with each genotype differs from the expected number of individuals with each genotype.

The population is not at Hardy-Weinberg equilibrium.

Explanation:

The FB allele should accounts for 120 of the alleles (40 × 2 = 80 in FBFB wolves, + 40 × 1 = 40 in FBFW wolves).

the FB allele would make up 20% (120/600) of the total alleles in the population, so the value of p would be 0.2. The allele frequencies of the population must add up to one for it to be valid (what this means is p+q=1); therefore, since the value of p is 0.2, and the value of q is 0.8.

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