What is the equation of the line that is parallel to line 2y+3x=4 and passes through the point (6, -2)
1 answer:
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Answer:
(3, 0 )
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c (a ≠ 0 )
Then the x- coordinate of the vertex is
= -
y = 5x² - 30x + 45 ← is in standard form
with a = 5, b = - 30 , then
= -
= 3
Substitute x = 3 into the function for corresponding value of y
y = 5(3)² - 30(3) + 45 = 45 - 90 + 45 = 0
vertex = (3, 0 )
