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lukranit [14]
3 years ago
13

W+8=-3 i don't understand how to solve the problem

Mathematics
2 answers:
Bogdan [553]3 years ago
8 0

Answer:

It is negetive 11

Step-by-step explanation:

First you need to subtract -3-8 and you will get -11.

This is called inverse operation

icang [17]3 years ago
4 0
First subtract 8 on the left side. what you do to the left Side you have to do to the right side. so then you should get -11. then since there in no number infront of the w, put a 1. then divide 1w/1 to cancel it out. and again what you do to one side you do to the other so then divide -11/1 which equals -11. hope you understand it.
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Explain how you can round 25.691 to the greatest place.
labwork [276]
If it is to the tenth, then you have to look at the hundredth place, if the number in the hundredth place is over 5 or 5, then you have to make the number in the tenth place move up one digit if it isn't over 5 or 5, then you don't do anything
4 0
3 years ago
Read 2 more answers
Can some find the area to this triangle I tried a bunch of things and i keep getting it wrong
Dafna1 [17]

Answer:

The answer to your question is 287.52 u²

Step-by-step explanation:

To calculate the area of a triangle it is necessary to have the base and the high of this figure.

Base = 35 km

height = ?

To calculate the height draw a right triangle and use the trigonometric function sin to find it.

sin Ф = \frac{opposite side}{hypotenuse}

Opposite side = hypotenuse x sinФ

Opposite side = height = 37 x sin28

                                     = 16.43 km

Calculate the area

              Area = (1/2)(35)(16.43)

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7 0
3 years ago
Due Soon Need Help Geometry!
AveGali [126]

 

Some basic formulas involving triangles

\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa  2 =b  2+2 + c 2

−2bc cos α

\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab   2=

 

m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m   b2 = 41(2a 2 + 2c 2-b 2)

b

Bisector formulas

\ \frac{a}{b} = \frac{m}{n}  ba =nm  

​  

 

\ l^2 = ab - mnl  2=ab-mm

A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=  

\ A = \sqrt{p(p - a)(p - b)(p - c)}A=  

p(p−a)(p−b)(p−c)

​  

 

\iits whatever  A = prA=pr with r we denote the radius of the triangle inscribed circle

\ A = \frac{abc}{4R}A=  

4R

abc

​  

 - R is the radius of the prescribed circle

\ A = \sqrt{p(p - a)(p - b)(p - c)}A=  

p(p−a)(p−b)(p−c)

​  

5 0
3 years ago
I need help plz plz hlep
Rudik [331]

it looks like its constant but I could be wrong

8 0
3 years ago
Simplify 4^3•4^5.<br> help asap !
Julli [10]

Answer:

D

Step-by-step explanation:

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7 0
4 years ago
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