Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
Answer:
2
Step-by-step explanation:
Answer:
( 5x+3y=7. < 3x - 5y = -23 you can use many ..
Step-by-step explanation:
hopefully its right
Answer:
25 in.
Step-by-step explanation:
DEC is a right triangle. <DEC is a right angle.
(DE)² + (EC)² = (DC)²
DE = ½DB = ½(48 in.) = 24 in.
(24 in.)² + (7 in.)² = (DC)²
576 in.² + 49 in.² = (DC)²
(DC)² = 625 in.²
DC = 25 in.