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Lunna [17]
4 years ago
13

Consider a processor with a clock rate of 4.5 GHz and an average CPI of 2. Suppose the processor executes a program in 10 second

s. What is the number of cycles executed by this processor during the program? * 109 What is the number of instructions executed by this processor during the program? * 109
Computers and Technology
1 answer:
alexandr1967 [171]4 years ago
6 0

Answer:

instruction executed = cycles executed / CPI = 45 x 109 / 2 = 22.5 x 109

Modification:

reduce execution time by 20 %

CPI increased by 25%

Explanation:

What is number of instructions executed by this processor during the program?

Answer:

instruction executed = cycles executed / CPI = 45 x 109 / 2 = 22.5 x 109

Modification:

reduce execution time by 20 %

CPI increased by 25%

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3 years ago
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vfiekz [6]
I believe that is true

Hope this helps!! :)

8 0
3 years ago
Give a big-O estimate for the number additions used in this segment of an algorithm.
rjkz [21]
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(I'm assuming that := is a typo and you mean just =, by the way) 

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This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.

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As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2). 

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4 years ago
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den301095 [7]
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4 0
4 years ago
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Y_Kistochka [10]

import random

database = {}

while True:

   try:

       user_choice = int(input("Enter your student id to bring up your information (Press enter if you don't have one) : "))

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           print("Student ID:",database[user_choice][0],"\nFirst name:",database[user_choice][1],"\nLast name:",database[user_choice][2],"\nPhone number:",database[user_choice][3],"\nEmail address:",database[user_choice][4],"\nPassword:",database[user_choice][5],"\nPoints:",database[user_choice][6])

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           student_id = random.randint(1,1000)

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I wrote my code in python 3.8. I hope this helps.

6 0
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