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Inessa [10]
3 years ago
7

Is dilated by a scale factor of 3 to form . Point O, which lies on , is the center of dilation.

Mathematics
1 answer:
Amanda [17]3 years ago
5 0

Answer:

qui qeruete  va a lmismiasima mierda  hjo dle uta pyalae mculosso

Step-by-step explanation:

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Use the figure and flowchart proof to answer the question:
KatRina [158]

Answer:

tSubstitution Property of Equality

Step-by-step explanation:

I took the test and that was the answer

4 0
3 years ago
Write the equation in spherical coordinates. (a) x2 y2 z2 = 64
vekshin1

The equation in spherical coordinates will be a constant, as we are describing a spherical shell.

r(φ, θ) = 8 units.

<h3>How to rewrite the equation in spherical coordinates?</h3>

The equation:

x^2 + y^2 + z^2 = R^2

Defines a sphere of radius R.

Then the equation:

x^2 + y^2 + z^2 = 64

Defines a sphere of radius √64 = 8.

Then we will have that the radius is a constant for any given angle, then we can write r, the radius, as a constant function of θ and φ, the equation will be:

r(φ, θ) = 8 units.

If you want to learn more about spheres, you can read:

brainly.com/question/10171109

8 0
1 year ago
The circumference of a circle is 29.83 cm. What are the radius and diameter, respectively? Use 3.14 for pi.
nasty-shy [4]

Answer:

Diameter: 9.5

Radius: 4.75

Step-by-step explanation:

To find the diameter you divide the circumference by pi(3.14) and to find radius you divide the diameter by 2 since the radius is half of the diameter.

Hope this helps you

7 0
2 years ago
3/4 of the weight of a bunch of grapes is equivalent to 3/5 of the weight of a papaya. If the grapes way (X +28) pounds what is
Margaret [11]
Let p = weight of papaya and g = weight of grapes.

Then (3/4)g = (3/5)p.  Since the weight of grapes is x + 28, 

(3/4)(x + 28) = (3/5)p.  We must solve for x.  To do this, mult. both sides by (5/3):

(5/3)(3/4)(x+28) = (5/3)(3/5)p

Then p = (15/9)(x+28), or (after reduction), p = (5/3)(x+28).


4 0
2 years ago
If BTS=GHD BS=25 TS=14 BT=31 GD=4x-11 S=56 B=21 and H=(7y+5) find the values of x and y
77julia77 [94]

Given:

Consider the completer question is "If ∆BTS≅∆GHD, BS=25, TS=14, BT=31, GD=4x-11, m∠S=56, m∠B=21 and m∠H=(7y+5), find the values of x and y.

To find:

The values of x and y.

Solution:

We have,

\Delta BTS\cong \Delta GHD       (Given)

BS=GD                       (CPCTC)

25=4x-11

25+11=4x

36=4x

Divide both sides by 4.

9=x

In ∆BTS,

\angle B+\angle T+\angle S=180^\circ    (Angle sum property)

21^\circ+\angle T+56^\circ=180^\circ

77^\circ+\angle T=180^\circ

\angle T=180^\circ-77^\circ

\angle T=103^\circ

Now,

\angle T=\angle H            (CPCTC)

103=7y+5

103-5=7y

98=7y

Divide both sides by 7.

14=y

Therefore, the value of x is 9 and value of y is 14.

3 0
2 years ago
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