I a pretty sure it is 228,000 but i am not sure.
Answer:
D : 10ab√2a+20a√2a
Step-by-step explanation:
Answer: Option 3 = 4
Step-by-step explanation: f(x) = 6 - 2x
f(0) = 6 - 2(0) Range = 6
f(2) = 6 - 2(2) Range = 2
f(4) = 6 - 2(4) Range = -2
f(6) = 6 - 2(6) Range = -6
f(8) = 6 - 2(8) Range = -10
The only one that doesn't belong is 4 option 3.
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Nighty Night!!!
Answer:
<em>80.7 ft/sec</em>
Step-by-step explanation:
You need two conversion factors:
1 mile = 5280 ft, so (52780 ft)/(1 mile) = 1
1 hour = 3600 seconds, so (1 hour)/(3600 seconds) = 1
55 mi/hour * (5280 ft)/(1 mile) * (1 hour)/(3600 seconds) = 80.6666... ft/sec
Answer: 80.7 ft/sec
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
