Ask question

Ask question

All categories

3 years ago

13

What does a isosceles triangle look like

2 answers:

professor190 [17]3 years ago

5 0

An isosceles triangle is a triangle with no equal sides.

S_A_V [24]3 years ago

4 0

Can i also have a 5 star rating and can you press the Thanks button

You might be interested in

1/2*(6*1+7)+11 show the result

fomenos

Well I got 17.5
You would start with 6x1=6
Then you would add 7: 6+7=13
Next you would multiply 13 by (1/2): 13(1/2)=6.5
Finally you would add 11 to 6.5: 6.5+11= 17.5

3 0

2 years ago

Given the function f(x)=x^2 and the transformed function g(x)=4x^2+1, explain how the parent function was transformed.

satela [25.4K]

Answer:

In the function g(x) = 4x² + 1, <em>4</em> means that all the points in the parent function were multiplied by 4. <em>+ 1 </em>means that the parent graph will shift up by 1.

4 0

2 years ago

Use the graph to find out over what interval f(x) is less than or equal to 0. PLEASE HELP ASAP!!!

jok3333 [9.3K]

Answer:

[-5, 2]

Step-by-step explanation:

We have to find the interval for which f(x) <= 0, the interval is [-5, 2].

5 0

2 years ago

A marketing consultant observed 40 consecutive shoppers to estimate the average money spent by shoppers in a supermarket store.

KonstantinChe [14]

Answer:

0.998 is the probability that the average money spent by a sample of 40 shoppers is within $10 of the actual population mean.

Step-by-step explanation:

We are given the following information in the question:

Standard Deviation, σ = $21.51

We are given that the distribution of average money spend is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

We have to find:

P( average money spent is within $10 of the actual population mean.)

$= P( z \leq \displaystyle\frac{10\times \sqrt{40}}{21.51}}) = P(z \leq 2.94)$

Calculation the value from standard normal z table, we have,

$P(z \leq 2.94) = 0.998$

6 0

2 years ago

Match each power of a power expression with its simplified expression.

VARVARA [1.3K]

Answer:

> $(4^6)^{-3}$ = $\frac{1}{4 ^ {18}}$

> $(4^{-3})^{-3}$ = $4 ^ 9$

> $(4^0)^{-9}$ = $4 ^0$

> $(-4^{-9})^2$ = $(-4) ^ {-18}$

Step-by-step explanation:

We have to expand the powers of each of them:

> $(4^6)^{-3}$ = $4^{(6 * -3)}$

= $4 ^ {-18}$

$(4^6)^{-3}$ = $\frac{1}{4 ^ {18}}$

> $(4^{-3})^{-3}$ = $4 ^ {(-3 * -3)}$

$(4^{-3})^{-3}$ = $4 ^ 9$

> $(4^0)^{-9}$ = $4 ^ {(0 * -9)}$

$(4^0)^{-9}$ = $4 ^0$

> $(-4^{-9})^2$ = $-4 ^ {( -9 * 2)}$

$(-4^{-9})^2$ = $-4 ^ {-18}$

8 0

2 years ago

Read 2 more answers