The volume of the cone is: A. 213 ft³.
<h3>Volume of a Cylinder and a Cone</h3>
- Volume of cylinder = πr²h.
- Volume of cone = ⅓πr²h.
Given:
radius and height of both the cylinder and the cone are equal.
Volume of Cylinder = 639 ft³
Therefore:
πr²h = ⅓πr²h
This means that volume of cone would be ⅓ of the volume of the cylinder.
Volume of cone = ⅓(639) = 213 ft³
Therefore, the volume of the cone is: A. 213 ft³.
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V=u+at
4=u+1a
2=u+2a
subtract
2=-a
a=-2
4=u-2
u=6
v=6-2t
or y=6-2x
or y=-2x+6
I believe the answer is 60%
Subsitution
2y-x=5
minus 2y both sides
-x=5-2y
times -2 both sides
x=2y-5
subsitute 2y-5 for x in other equation
(2y-5)²+y²-25=0
expand
4y²-20y+25+y²-25=0
5y²-20y=0
factor
5y(y-4)=0
set to zero
5y=0
y=0
y-4=0
y=4
subsitute back
for y=0
x=2y-5
x=2(0)-5
x=-5
one solution is (-5,0)
for x=4
x=2y-5
x=2(4)-5
x=8-5
x=3
one solution is (3,4)
the 2 soltuions are (-5,0) and (3,4)
