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3 years ago

Please help answer circled questions and show work if you want

Mathematics

1 answer:

vazorg [7]3 years ago

5 0

2 x = 72

4 n = 7.5

6 no solution (the variable cancelled itself out)

8 no solution

10 x = 43

12 y=-5.83-x

14 (P-2l)/2 = w

16 Your team's score was 85 (because you scored 13 more points than the other team and 72 + 13 = 85).

18 The other scientist had the greater temperature (950 C > 1725 F), since 950 C = 1742 F

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Mercury orbits the sun in 87 24/25 Earth days. Venus orbits the sun in 224 7/10 Earth days, and Mars orbits the sun in 686 49/50

kompoz [17]

mercury 2,199 = 24 + 25 × 87 and divide 2,199/25
= 87.96

Venus (2,240 + 7 )/10 = 224.7

Mars = 686.98

8 0

3 years ago

Solve for x rounded to the nearest tenth. sin 52 =x/7

babunello [35]

Answer:

6.9

Step-by-step explanation:

sin(52)=x

x=7sin(52)

6 0

3 years ago

Kirby is packing granola bars for a field trip. He already packed 2 bags

hoa [83]

Answer:

none

Step-by-step explanation:

1. Kirby sucked it all up

5 0

3 years ago

Find the equation of the lines parallel and perpendicular to the line 5x+2y=12 through the point (-2,3)

muminat

Answer:

The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Step-by-step explanation:

Given equation of line as :

5 x + 2 y = 12

or, 2 y = - 5 x + 12

or , y = $\frac{-5}{2}$ x + $\frac{12}{2}$

Or, y = $\frac{-5}{2}$ x + 6

∵ Standard equation of line is give as

y = m x + c

Where m is the slope of line and c is the y-intercept

Now, comparing given line equation with standard eq

So, The slope of the given line = m = $\frac{-5}{2}$

Again,

The other line if passing through the points (- 2 , 3 ) And is parallel to given line

So, for parallel lines condition , the slope of both lines are equal

Let The slope of other line = M

So, M = m = $\frac{-5}{2}$

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M x + c

Now , satisfying the points

So, 3 = $\frac{-5}{2}$ × ( - 2 ) + c

or, 3 = $\frac{10}{2}$ + c

Or, 3 = 5 + c

∴ c = 3 - 5 = - 2

c = - 2

So, The equation of line with slope $\frac{-5}{2}$ and passing through points ( -2 , 3)

y = $\frac{-5}{2}$ x - 2

or, 2 y = - 5 x - 4

I.e 5 x + 2 y + 4 = 0

Similarly

The other line if passing through the points (- 2 , 3 ) And is perpendicular to given line

So, for perpendicular lines condition,the products of slope of both lines = - 1

Let The slope of other line = M'

So, M' × m = - 1

Or, M' × $\frac{-5}{2}$ = - 1

Or, M' = $\frac{-1}{\frac{-5}{2}}$

Or, M' = $\frac{2}{5}$

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M' x + c'

Now , satisfying the points

So, 3 = $\frac{2}{5}$ × ( - 2 ) + c'

or, 3 = $\frac{- 4}{5}$ + c'

Or, 3 × 5 = - 4 + 5× c'

∴ 5 c' = 15 + 4

or, 5 c' = 19

Or, c' = $\frac{19}{5}$

So, The equation of line with slope $\frac{2}{5}$ and passing through points ( -2 , 3)

y = $\frac{2}{5}$ x + $\frac{19}{5}$

y = $\frac{2 x + 19}{5}$

Or, 5 y = 2 x + 19

Or, 2 x - 5 y + 19 = 0

Hence The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

And The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Answer

4 0

3 years ago

(06.04 MC)What is the volume of four cubes with a side length of fraction 1 over 4 foot? V = s3, where s is the side length.

PIT_PIT [208]

Volume of 1 cube = s^3

s= side

so, vol = (1/4)^3 = 1 / 64

Now, there are 4 cubes:
So, volume of 4 cubes = (1 / 64 ) x 4 = 1 /16

Unit will obviously be foot^3

7 0

3 years ago

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