4 x 1/8w -> 4/8 w -> 1/2 w
1/2w -3/5 x
Hope this helps!
Answer:
Step-by-step explanation:
This is good! The length of the metal is 20 inches longer than the width. But we fold up 4-inch flaps on each side, so the height of the box is 4 inches, and the length and width will each decrease by 8 inches (4 inches on each side). Since the length and width decrease by the same amount, the length will still be 20 inches longer than the width. So the equations would be:
l = w + 20
vol = l x w x h = 1716 in3
1716 = (w + 20)(w)(4)
1716 = 4w2 + 80w
4w2 + 80w - 1716 = 0
4(w2 + 20w - 429) = 0
4(w + 33)(w - 13) = 0
w + 33 = 0, so w = -33
w - 13 = 0, so w = 13
Since the width can't be negative, the width of the box is 13 and the length is 33 (13 + 20).
But remember, the length and width of the piece of metal are each 8 inches longer than the box, so it was 41 inches by 21 inches.
Answer:
multiply the things in the () with6
Step-by-step explanation:
Answer: 110
Step-by-step explanation:
Given;
Total cost C = $151
Enrollment fee E = $30
Charge per 10 test t = $11
n is the number of packet of test taken.
The questions can be represented by the equation below;
30 + 11n = 151
Substracting 30 from both sides.
11n = 151-30 = 121
n = 121/11
n = 11
Since the number of packet of test is 11 and each packet contains 10 tests. The number of test N is given by;
N = 10 n = 10 ×11 = 110
N = 110
Answer:
4 is the length
Step-by-step explanation:
14 and 4
14 x 14 + 4 x 4 = 212
14 + 4 = 18
